如何在php中修复格式错误的JSON [英] how to fix a malformed JSON in php

问题描述

我有这个JSON字符串，我想使用json_decode();函数对其进行解码

i have this JSON string that i want to decode it with json_decode(); function

{"phase":2,"id":"pagelet_profile_picture","css":["VCxcl","Ix2pq"],"js":["fZYUE","VfnZ3"],"content":{"pagelet_profile_picture":"\u003cdiv class=\"profile-picture\">\u003cspan class=\"profile-picture-overlay\">\u003c\/span>\u003cimg class=\"photo img\" src\=\"http:\/\/profile.ak.fbcdn.net\/hprofile-ak-snc4\/222_111_2222_n.jpg\" alt=\"bla bla\" id=\"profile_pic\" \/>\u003c\/div>"}}

有json_last_error();，但对我没有帮助. (有时会获取JSON_ERROR_STATE_MISMATCH和JSON_ERROR_SYNTAX)

there is the json_last_error(); but it not helping me. (got JSON_ERROR_STATE_MISMATCH and JSON_ERROR_SYNTAX sometimes)

我想知道此JSON字符串出了什么问题以及如何在PHP中自动修复它，以便可以对其进行解码. 一些代码将非常有帮助 谢谢.

i want to know what wrong with this JSON string and how i can fix it automatically in PHP so i can decode it. some code will be very helpful thanks.

推荐答案

使用json lint，看来问题出在src \ =

Using a json lint, it seems the problem is the src\=

\转义=符号，这没有任何意义.

the \ escapes the = sign, which makes no sense.

如果将src \ =替换为src =，它将通过验证程序.

If you replace src\= with src= it passes the validator.

解决方法:

1. 首先修复生成json字符串的代码.

或

1. 使用 str_replace 将'src \ ='更改为'src ='

1. use str_replace to change 'src\=' to 'src='

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