如何根据位置对字典中的值求和? [英] How to sum values in dictionary based on position?

问题描述

我有一个字典，其中每个键在列表中都有五个值，例如:

I have a dictionary that for each key there are five values in list, such as:

{"A": [0, 0.12, 0, 0.73, 0], "B": [0.96, 0, 0.30, 0, 0],
  "C": [0, 0, 0, 0.11, 0],    "D": [0, 0.07, 0, 0.42, 0]}

我想对所有键的第一，第二等值求和，然后将其添加到新列表中，例如:

I want to sum first, second and etc. values for all keys and add it in new list such as:

[0.96, 0.19, 0.3, 1.26, 0]

我尝试通过下面的代码解决它，但是没有用:

I tried by below code solve it but It didn't work:

aa = {"A": [0, 0.12, 0, 0.73, 0], "B": [0.96, 0, 0.30, 0, 0], "C": [0, 0, 0, 0.11, 0], "D": [0, 0.07, 0, 0.42, 0]}
bb = []
for value in (aa.items()):
    for item in value:
        bb.append(item)

推荐答案

您可以使用zip()函数

aa = {"A": [0, 0.12, 0, 0.73, 0], "B": [0.96, 0, 0.30, 0, 0], "C": [0, 0, 0, 0.11, 0], "D": [0, 0.07, 0, 0.42, 0]}
bb = []

for value in (zip(*list(aa.values()))):
           bb.append(sum(value))


print (bb)  

输出:

 [0.96, 0.19, 0.3, 1.26, 0]

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