如何在bash中使用kill SIGUSR2? [英] how to use kill SIGUSR2 in bash?

问题描述

我使用iptraf监视linux中的网络流量，而shell命令是(使iptraf在后台运行):

I use iptraf to monitor the network traffic in linux, and the shell command is(make iptraf running in background):

iptraf -s eth0 -f -B -L ./traffic.dat

如果要得到结果，我必须先停止iptraf，所以我使用shell命令:

if I want to get the result, I have to stop iptraf first, so I use the shell command:

kill -SIGUSR2 $pid

但是，如果我将这些shell命令移到bash脚本文件(net.sh)中，我将无法停止iptraf，但会收到错误消息:

however, I could not stop iptraf if I move these shell commands into a bash script file(net.sh), and I get an error:

kill: SIGUSR2: invalid signal specification

我在脚本文件(net.sh)中使用了"kill -l"，但是我发现没有名称为SIGUSR2的参数.如果我使用USR2或-9，我将一无所获.

I use 'kill -l' in the script file(net.sh), and I find there is no parameter which name is SIGUSR2. and I would get nothing if I use USR2 or -9.

完整的脚本文件是:

    iptraf -s eth0 -f -B -L ./temp.txt
    pid=`ps -ef | grep iptraf | grep -v grep | awk '{print $2}'`
    kill -USR2 $pid
    cat temp.txt

这些命令后我什么也没得到.

I get nothing after these commands.

如果我想得到结果该怎么办?

what shoud I do if I want to get the result?

推荐答案

SIGUSR2是依赖于体系结构的，并且其值可以超出31，12或17. man 7 signal 中对此进行了描述.您必须找出哪个值适合您的系统.通常，这可以通过查看以下内容来完成:

SIGUSR2 is architecture depended and can have a value out of 31, 12 or 17. This is described in man 7 signal. You'll have to find out which value is appropriate for your system. Usually this is done by having a look into:

/usr/include/asm/signal.h 

在我的系统上-Ubuntu 12.04 AMD 64-其值为12:

On my system - Ubuntu 12.04 AMD 64 - it has a value of 12:

#define SIGUSR2     12

一旦您知道系统上SIGUSR2的正确数值，就可以使用以下方式发送该信号:

Once you know the proper numeric value for SIGUSR2 on your system, you can send this signal using:

kill -SIGNO PID
# In this case
kill -12 PID

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