用索引中的一条线连接两组点 [英] Connect two set of points with a line based in the index

问题描述

我想做的是用线连接两组点(基于x，y).应基于两组的索引绘制线.含义set1(x,y)应该连接到set2(x,y)，其中x和y是两组中相同的索引.

What I'm trying to do is connecting two sets of points (x,y based) with a line. The line should be drawn based on the index of the two sets. Meaning set1(x,y) should be connected to set2(x,y) where x and y are the same indices in both sets.

到目前为止，我的工作是:

What I have so far is the following:

set1 = [1,2; 3,4; 5,6];
set2 = [10,20; 30,40; 50,60];
plot(set1(:,1),set1(:,2),'b+',set2(:,1),set2(:,2),'g+')

以蓝色点显示set1的项目，以绿色点显示set2的项目.意思是我想在[1,2]和[10,20]

Displaying me the items of set1 in blue points and the set2 in green points. Meaning I want to plot a line between [1,2] and [10,20]

是否有任何内置函数，或者是否需要创建代表行的第三组，例如[ [1,2; 10,20], [3,4; 30,40], ... ]?

Is there any build-in function for this, or do I need to create a third set representing the lines e.g. [ [1,2; 10,20], [3,4; 30,40], ... ]?

推荐答案

您不需要构建函数，只需正确使用plot.如果输入x值矩阵和y值矩阵，则plot会将其解释为多个数据系列，其中每一列都是一个数据系列.

You don't need to build a function, just to use plot correctly. If you input a matrix of x values and a matrix of y values, then plot interprets it as multiple series of data, where each column is a data series.

因此，如果您进行重组，则设置为:

So if you reorganize you sets to:

x = [set1(:,1) set2(:,1)].'
y = [set1(:,2) set2(:,2)].'

然后您可以输入:

plot(x,y)

包含我们数据的代码:

set1 = [1,2; 3,4; 5,6];
set2 = [10,20; 30,40; 50,60];
plot(set1(:,1),set1(:,2),'b+',set2(:,1),set2(:,2),'g+')
hold on
x = [set1(:,1) set2(:,1)].';
y = [set1(:,2) set2(:,2)].';
plot(x,y,'r')
hold off

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