在Linux Bash中，双与号(&&)和分号(;)之间有什么区别? [英] What is the difference between double-ampersand (&&) and semicolon (;) in Linux Bash?

问题描述

Linux Bash 中的&符和分号有什么区别? >

例如，

$ command1 && command2

vs

$ command1; command2

解决方案

&&运算符是布尔AND运算符:如果左侧返回非零退出状态，则该运算符将返回该状态并且不评估右侧(短路)，否则评估右侧并返回其退出状态.这通常用于确保command2仅在command1成功运行时才运行.

;令牌只是分隔命令，因此无论第一个命令是否成功，它都会运行第二个命令.

What is the difference between ampersand and semicolon in Linux Bash?

For example,

$ command1 && command2

vs

$ command1; command2

解决方案

The && operator is a boolean AND operator: if the left side returns a non-zero exit status, the operator returns that status and does not evaluate the right side (it short-circuits), otherwise it evaluates the right side and returns its exit status. This is commonly used to make sure that command2 is only run if command1 ran successfully.

The ; token just separates commands, so it will run the second command regardless of whether or not the first one succeeds.

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