Linux Shell脚本-带通配符的字符串比较 [英] Linux Shell Script - String Comparison with wildcards

问题描述

我正在尝试查看一个字符串是否是Shell脚本(#！bin/sh)中另一个字符串的一部分.

I am trying to see if a string is part of another string in shell script (#!bin/sh).

我现在拥有的代码是:

#!/bin/sh
#Test scriptje to test string comparison!

testFoo () {
        t1=$1
        t2=$2
        echo "t1: $t1 t2: $t2"
        if [ $t1 == "*$t2*" ]; then
                echo "$t1 and $t2 are equal"
        fi
}

testFoo "bla1" "bla"

我要寻找的结果是，我想知道"bla1"中何时存在"bla".

The result I'm looking for, is that I want to know when "bla" exists in "bla1".

谢谢和亲切的问候，

更新: 我已经尝试了两个包含"功能，如下所述:

UPDATE: I've tried both the "contains" function as described here: How do you tell if a string contains another string in Unix shell scripting?

以及 bash中包含的字符串中的语法

但是，它们似乎与普通的shell脚本(bin/sh)不兼容...

However, they seem to be non compatible with normal shell script (bin/sh)...

帮助?

推荐答案

在bash中，您可以编写(请注意，星号在引号的外部之外)

In bash you can write (note the asterisks are outside the quotes)

    if [[ $t1 == *"$t2"* ]]; then
            echo "$t1 and $t2 are equal"
    fi

对于/bin/sh，=运算符仅用于相等性，不适用于模式匹配.您可以使用case

For /bin/sh, the = operator is only for equality not for pattern matching. You can use case though

case "$t1" in
    *"$t2"*) echo t1 contains t2 ;;
    *) echo t1 does not contain t2 ;;
esac

如果您专门针对linux，则假定存在/bin/bash.

If you're specifically targetting linux, I would assume the presence of /bin/bash.

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