在shell脚本中创建重复字符的字符串 [英] Creating string of repeated characters in shell script

问题描述

我需要生成一串点(.characters)作为变量.

I need to generate a string of dots (.characters) as a variable.

即，在我的 Bash 脚本中，对于输入 15，我需要生成长度为 15 的字符串:.................

I.e., in my Bash script, for input 15 I need to generate this string of length 15: ...............

我需要不断地这样做.我尝试使用它作为基础(来自 Unix.com):

I need to do so variably. I tried using this as a base (from Unix.com):

for i in {1..100};do printf "%s" "#";done;printf "\n"

但是如何让 100 成为一个变量?

But how do I get the 100 to be a variable?

推荐答案

您可以从/dev/zero 获取任意数量的 NULL 字节.然后，您可以将这些转换为其他字符.下面打印16个小写的a

You can get as many NULL bytes as you want from /dev/zero. You can then turn these into other characters. The following prints 16 lowercase a's

head -c 16 < /dev/zero | tr '\0' '\141'

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