将列表的字符串表示形式转换为实际的列表对象 [英] Converting a string representation of a list into an actual list object

问题描述

我有一个看起来与列表相同的字符串，比方说:

I have a string that looks identical to a list, let's say:

fruits = "['apple', 'orange', 'banana']"

将其转换为列表对象的方式是什么?

What would be the way to convert that to a list object?

推荐答案

>>> fruits = "['apple', 'orange', 'banana']"
>>> import ast
>>> fruits = ast.literal_eval(fruits)
>>> fruits
['apple', 'orange', 'banana']
>>> fruits[1]
'orange'

如评论中所指出的， ast.literal_eval 是安全.从文档中:

As pointed out in the comments ast.literal_eval is safe. From the docs:

安全地评估表达式节点或包含Python的字符串 表达.提供的字符串或节点只能由 以下Python文字结构:字符串，数字，元组，列表， dicts，booleans和None.

Safely evaluate an expression node or a string containing a Python expression. The string or node provided may only consist of the following Python literal structures: strings, numbers, tuples, lists, dicts, booleans, and None.

这可用于安全地评估包含Python的字符串 来自不受信任来源的表达式，无需解析 珍惜自己.

This can be used for safely evaluating strings containing Python expressions from untrusted sources without the need to parse the values oneself.

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