如何将列表的字符串表示形式转换为列表? [英] How to convert string representation of list to a list?

问题描述

我想知道将如下列表的字符串表示形式转换为 list 的最简单方法是什么:

I was wondering what the simplest way is to convert a string representation of a list like the following to a list:

x = '[ "A","B","C" , " D"]'

即使在用户在逗号之间和引号内放置空格的情况下，我也需要处理它并将其转换为:

Even in cases where the user puts spaces in between the commas, and spaces inside of the quotes, I need to handle that as well and convert it to:

x = ["A", "B", "C", "D"] 

我知道我可以使用 strip() 和 split() 去除空格并检查非字母字符.但是代码变得非常混乱.是否有我不知道的快速功能?

I know I can strip spaces with strip() and split() and check for non-letter characters. But the code was getting very kludgy. Is there a quick function that I'm not aware of?

推荐答案

>>> import ast
>>> x = '[ "A","B","C" , " D"]'
>>> x = ast.literal_eval(x)
>>> x
['A', 'B', 'C', ' D']
>>> x = [n.strip() for n in x]
>>> x
['A', 'B', 'C', 'D']

ast.literal_eval:

使用 ast.literal_eval，您可以安全地计算表达式节点或包含 Python 文字或容器显示的字符串.提供的字符串或节点只能包含以下 Python 文字结构:字符串、字节、数字、元组、列表、字典、布尔值和 None.

With ast.literal_eval you can safely evaluate an expression node or a string containing a Python literal or container display. The string or node provided may only consist of the following Python literal structures: strings, bytes, numbers, tuples, lists, dicts, booleans, and None.

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