如何将列表转换为xml字符串，将xml转换为列表 [英] how to convert list to xml string and xml to list

问题描述

public class FeePlanGenerate
    {
        public List<FeePlan> FeePlanList { get; set; }
        public List<FeeComponent> FeeComponentList { get; set; }

        public string StudentName { get; set;}
        public string StudentAddress { get; set; }
        public string CurriculumName { get; set; }
        public string CourseName { get; set; }
        public string BCNumber { get; set; }
        public Nullable< DateTime> AddmissionDate { get; set; }
        public string AddmissionOfficer{ get; set; }
        public string Contant1 { get; set; }
        public string Contant2 { get; set; }
        public string AdmissionCode { get; set; }
        public Nullable< decimal> TotalInvoiceAmount { get; set; }
        public Nullable<decimal> TotalPayableFee { get; set; }
        public string ArrayOfFeePlanGenerate { get; set; }
    }

推荐答案

嗨Ahsan70，

Hi Ahsan70,

>>如何将列表转换为xml字符串，将xml转换为列表

>>how to convert list to xml string and xml to list

我做了一个简单的演示为此，请参考下面的内容。

I make a simple demo for this purpose, please refer to it as below.

创建一个用于序列化和反序列化的类：

Create a class used for serialization and deserialization:

    // serialization and deserialization
    public class XmlUtil
    {
        #region deserialization
        // deserialization
        public static object Deserialize(Type type, string xml)
        {
            try
            {
                using (StringReader sr = new StringReader(xml))
                {
                    XmlSerializer xmldes = new XmlSerializer(type);
                    return xmldes.Deserialize(sr);
                }
            }
            catch (Exception e)
            {

                return null;
            }
        }
        // deserialization
        public static object Deserialize(Type type, Stream stream)
        {
            XmlSerializer xmldes = new XmlSerializer(type);
            return xmldes.Deserialize(stream);
        }
        #endregion

        #region serialization
        // serialization
        public static string Serializer(Type type, object obj)
        {
            MemoryStream Stream = new MemoryStream();
            XmlSerializer xml = new XmlSerializer(type);
            try
            {
                //Serialized object
                xml.Serialize(Stream, obj);
            }
            catch (InvalidOperationException)
            {
                throw;
            }
            Stream.Position = 0;
            StreamReader sr = new StreamReader(Stream);
            string str = sr.ReadToEnd();

            sr.Dispose();
            Stream.Dispose();

            return str;
        }
        #endregion
    }

然后我简化了您提供测试的课程：

Then I simplified the class that you provided for test as this:

    public class Student
    {
        public string Name { set; get; }
        public int Age { set; get; }
    }

然后达到如下目的：

        string xml;
        private void button1_Click(object sender, EventArgs e)
        {
            //Generate a List object for testing
            List<Student> list1 = new List<Student>(3);

            list1.Add(new Student() { Name = "James", Age = 33 });
            list1.Add(new Student() { Name = "Kobe", Age = 39 });
            //serialization
            xml = XmlUtil.Serializer(typeof(List<Student>), list1);
            Console.Write(xml);
        }

        private void button2_Click(object sender, EventArgs e)
        {
            //deserialization
            List<Student> list2 = XmlUtil.Deserialize(typeof(List<Student>), xml) as List<Student>;
            foreach (Student stu in list2)
            {
                Console.WriteLine(stu.Name + "," + stu.Age.ToString());
            }
        }

结果：

希望这会有所帮助！

问候，

Stanly

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