如何将XML（字符串）转换为有效文档？ [英] How to convert XML (String) to a valid document?

问题描述

我将XML作为字符串，我想将其转换为DOM文档以便使用XPath进行解析，我使用此代码将一个String元素转换为DOM元素：

I have XML as a string and i want to convert it to DOM document in order to parse it using XPath, i use this code to convert one String element to DOM element:

public Element convert(String xml) throws ParserConfigurationException, SAXException, IOException{

        Element sXml =  DocumentBuilderFactory
                .newInstance()
                .newDocumentBuilder()
                .parse(new ByteArrayInputStream(xml.getBytes()))
                .getDocumentElement();


        return  sXml;

    } 

但是如果我要转换整个XML文件怎么办？ ？我尝试了强制转换，但由于您无法从Element转换为Document（抛出异常）而无法正常工作：

but what if i want to convert a whole XML file?? i tried casting but it didn't work as you can't convert from Element to a Document(Exception thrown):

异常：

Exception in thread "main" java.lang.ClassCastException: com.sun.org.apache.xerces.internal.dom.DeferredElementImpl cannot be cast to org.w3c.dom.Document

代码：

public Document convert(String xml) throws ParserConfigurationException, SAXException, IOException{

        Element sXml =  DocumentBuilderFactory
                .newInstance()
                .newDocumentBuilder()
                .parse(new ByteArrayInputStream(xml.getBytes()))
                .getDocumentElement();


        return (Document) sXml;

    } 

我也尝试过这种方法，但是没有用：

i also tried this but didn't work:

public Document convert(String xml) throws ParserConfigurationException, SAXException, IOException{

        Document sXml =  DocumentBuilderFactory
                .newInstance()
                .newDocumentBuilder()
                .parse(new ByteArrayInputStream(xml.getBytes()));


        return  sXml;

    } 

我该怎么做才能解决此问题？

what can i do to fix this problem? and if there is a way in XPath to parse a String rather than a document it also will be fine.

推荐答案

也许可以通过使用XPath，并且在XPath中解析字符串而不是文档来解决问题。此

Maybe by using this

public static Document stringToDocument(final String xmlSource)   
    throws SAXException, ParserConfigurationException, IOException {  
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();  
    DocumentBuilder builder = factory.newDocumentBuilder();  

    return builder.parse(new InputSource(new StringReader(xmlSource)));  
}  

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