如何生成连续数字列表? [英] How can I generate a list of consecutive numbers?

问题描述

说，如果您在python中输入了数字8，并且想生成一个连续的数字列表，最高可达8，例如

Say if you had a number input 8 in python and you wanted to generate a list of consecutive numbers up to 8 like

[0, 1, 2, 3, 4, 5, 6, 7, 8]

你怎么能做到这一点?

推荐答案

在Python 3中，您可以使用内置的

In Python 3, you can use the builtin range function like this

>>> list(range(9))
[0, 1, 2, 3, 4, 5, 6, 7, 8]

注1::Python 3.x的range函数返回range对象.如果需要列表，则需要使用 list 功能就像我在答案中所示.

Note 1: Python 3.x's range function, returns a range object. If you want a list you need to explicitly convert that to a list, with the list function like I have shown in the answer.

注2:我们将数字9传递给range函数，因为range函数将生成直到给定数字的数字，但不包括该数字.因此，我们给实际数字+ 1.

Note 2: We pass number 9 to range function because, range function will generate numbers till the given number but not including the number. So, we give the actual number + 1.

注释3:在Python 2和3中，range的功能略有不同.您可以在

Note 3: There is a small difference in functionality of range in Python 2 and 3. You can read more about that in this answer.

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