如何使用嵌套的for循环的索引生成连续的数字列表? [英] How do I use the indices of nested for-loops to generate a consecutive list of numbers?

问题描述

例如:

for (int i = 0; i < 3; i++) {
  for (int j = 0; j < 4; j++) {
    for (int k = 0; k < 5; k++) {
      ...
    }
  }
}

那是执行最内部代码的3 * 4 * 5 = 60次.现在，我想使用索引i，j和k的值来生成从0到59(不一定要排序)的所有数字.

That's 3 * 4 * 5 = 60 times executing the innerst code. Now I want to use the values of the indices i, j, and k to generate all numbers from 0 to 59 (not necessarily sorted).

推荐答案

好，知道了.

使k数为1，j数为k的极限，我数为j的极限乘以k的极限.

Make k count 1, j count k's limit, i count j's limit times k's limit.

for (int i = 0; i < 3; i++) {
  for (int j = 0; j < 4; j++) {
    for (int k = 0; k < 5; k++) {
      int c = k * 1 + j * (5) + i * (5 * 4);
      System.out.println(c);
    }
  }
}

输出:0..59.

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