python分解列表 [英] python decompose a list

问题描述

我记得我曾经见过一个能够在python中分解列表的运算符.

I remember I once seen a operator which is able to decompose a list in python.

例如

[[1],[2],[3]]

通过应用该运算符，您将得到

by applying that operator, you get

[1], [2], [3]

该操作员是什么，任何帮助将不胜感激.

what is that operator, any help will be appreciated.

推荐答案

如果要将参数列表传递给函数，则可以使用splat运算符*.运作方式如下:

If you want to pass a list of arguments to a function, you can use *, the splat operator. Here's how it works:

list = [1, 2, 3]
function_that_takes_3_arguments(*list)

如果要将列表的内容分配给变量，则可以列出解压缩列表:

If you want to assign the contents of a list to a variable, you can list unpacking:

a, b, c = list # a=1, b=2, c=3

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