将列表转换为一行data.frame [英] Converting a list to one row data.frame

问题描述

我有一个这样的列表:

arg0 <- list(code = "a", n = rep(10, 3))

列表中的对象数是可变的.列表中的对象是矢量-只有一维对象.

The number of objects in a list is variable. The objects of the list are vectors -- only one dimensional objects.

我想制作一个将列表转换为一行的data.frame的过程，如下所示:

I want to make a procedure to convert the list to a one row data.frame like this:

> data.frame(code = "a", n.1 = 10, n.2 = 10, n.3 = 10)
  code n.1 n.2 n.3
1    a  10  10  10

我目前有此解决方案:

a <- stack(arg0)
b <- data.frame(t(a[,1]))
names(b) <- a[,2]
b <- data.frame(b)

b几乎是我想要达到的结果:

Where b is almost the result I want to achieve:

> b
  code  n n.1 n.2
1    a 10  10  10

两个问题:

1. 是否有更优雅的方法来达到目的?
2. 您是否知道如何获取重复的姓氏(如c(n.1, n.2, n.3))的编号?

1. Is there more elegant way to achieve the result?
2. Do you have any idea how to get the numbering of the duplicate colnames like c(n.1, n.2, n.3)?

推荐答案

如果要保留列表对象的不同数据类型，可以使用以下命令:

If you want to keep the different data types of the list's objects, the following command can be used:

data.frame(lapply(arg0, function(x) t(data.frame(x))))

输出:

  code n.1 n.2 n.3
x    a  10  10  10

第二到四列中的值仍然是数字.

The values in columns two to four are still numeric.

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