按功能对python列表进行排序 [英] Sort python list by function

问题描述

我有一个函数，该函数将一个对象作为参数并给我一个数字.我希望使用此数字作为对列表进行排序的键.

I have a function that takes an object as an argument and gives me a number. I wish to use this number as the key to sort my list.

如果要遍历列表，我会做类似的事情:

If I were to iterate over the list I would do something like:

sorted_list = []
for object in my_list_of_objects:
    i = my_number_giving_function(object)
    sorted_list.insert(i, object)

如何使用sorted来获得相同的结果，这是可取的吗?这是我想出的，但是我不知道要在"???"中添加什么?

How can I user sorted to get the same result, and is it advisable? This is what I came up with but I don't know what to put in the '???'

sorted_list = sorted(my_list_of_objects, key=my_number_giving_function(???))

推荐答案

sort(my_list_of_objects, key=my_number_giving_function)

与已排序相同，参见"Python排序方法"

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