我们如何用Java编写浮点数的二进制，八进制和十六进制文字? [英] How we can write binary, octal and hexadecimal literals of floating point numbers in Java?
问题描述
如何用Java编写浮点数的二进制，八进制和十六进制文字?无论是科学的还是正常的代表.
How we can write binary, octal and hexadecimal literals of floating point numbers in Java? Either in scientific or in normal representation.
class First
{
public static void main(String[] args)
{
double b = 0x12p3;
System.out.println(b);
}
}
以上程序结果为144.0
The above program results 144.0
class First
{
public static void main(String[] args)
{
double b = 0x12e3;
System.out.println(b);
}
}
以上程序结果为4835.0
The above program results 4835.0
class First
{
public static void main(String[] args)
{
double b = 0x12e3;
System.out.println(b);
}
}
以上程序结果为4835.0
The above program results 4835.0
class First
{
public static void main(String[] args)
{
double b = 012e3;
System.out.println(b);
}
}
上述计划的结果为12000
The above program results 12000
请解释以上输出.
推荐答案
第一个示例是HexadecimalFloatingPointLiteral，(16 + 2)* 8 = 144.
The first example is a HexadecimalFloatingPointLiteral, (16+2)*8 = 144.
第二个和第三个示例实际上是分配给双变量1 * 16 * 16 * 16 + 2 * 16 * 16 + 14 * 16 + 3 = 4835的HexIntegerLiteral.请注意，"e"只是十六进制14位数字.
The second and third example is actually a HexIntegerLiteral assigned to a double variable, 1*16*16*16 + 2*16*16 + 14*16 + 3 = 4835. Note that the 'e' is just the hex digit for 14.
最后一个示例是12 * 1000的DecimalFloatingPointLiteral.
The last example is a DecimalFloatingPointLiteral, 12 * 1000.
Java不支持八进制浮点文字.
Java does not support an octal floating point literals.
有关所有详细信息，请参见JLS: https://docs.oracle.com/javase/specs/jls/se8/html/jls-3.html#jls-3.10.2
For all the details see the JLS: https://docs.oracle.com/javase/specs/jls/se8/html/jls-3.html#jls-3.10.2
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