循环弹出窗口混乱 [英] loop popup confusion

问题描述

有人可以告诉我如何使我的URL正确循环到我创建的window.open中吗?我想知道循环是否是使每个URL根据我的setInterval旋转的正确答案?如果是，我想知道循环是否需要在var rotate = []{for (var i = 0; i < urls.length; i++)};下.

Can someone tell me how to make my URLs properly loop into the window.open I created? I’m wondering if the loop is the right answer to make each URL rotate based on my setInterval? If yes, I was wondering if the loop needs to be under var rotate = []{for (var i = 0; i < urls.length; i++)};.

var urls = ["http://www.espn.com","http://www.disney.com","http://www.codingforums.com"];
var rotate = 0;
function goRandom()
{
    var newwin = window.open(
        urls[ rotate ],
        "POPUP",
        "height=400,width=600,scrollbars=yes"
    );
}
var loop = setInterval(goRandom, 5000);

推荐答案

只需更改

urls[ rotate ],

到

urls[ (rotate++) % urls.length ],

索引在每次迭代时递增，并且% urls.length(％用于除法后获得余数，因此可确保结果永远不会超出数组大小).您可以在此处尝试(请记住允许弹出窗口).

The index is incremented each iteration and % urls.length (% is used for getting the remainder after division, hence it ensures the result never grows beyond the array size). You can try it here (remember to allow popups).

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