OS X的Bash脚本绝对路径 [英] Bash script absolute path with OS X

问题描述

我正在尝试获取OS X上当前正在运行的脚本的绝对路径.

I am trying to obtain the absolute path to the currently running script on OS X.

我看到许多对readlink -f $0的回复.但是，由于OS X的readlink与BSD的相同，所以它根本不起作用(它可以与GNU的版本一起使用).

I saw many replies going for readlink -f $0. However since OS X's readlink is the same as BSD's, it just doesn't work (it works with GNU's version).

是否有现成的解决方案?

Is there an out-of-the-box solution to this?

推荐答案

有一个realpath() C函数可以完成这项工作，但是我在命令行上看不到任何可用的东西.这是一个快速而肮脏的替代品:

There's a realpath() C function that'll do the job, but I'm not seeing anything available on the command-line. Here's a quick and dirty replacement:

#!/bin/bash

realpath() {
    [[ $1 = /* ]] && echo "$1" || echo "$PWD/${1#./}"
}

realpath "$0"

如果以/开头，则逐字打印路径.如果不是，它必须是相对路径，因此它将$PWD放在前面. #./部分从$1的前面剥离./.

This prints the path verbatim if it begins with a /. If not it must be a relative path, so it prepends $PWD to the front. The #./ part strips off ./ from the front of $1.

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