OS X 中的 Bash 脚本绝对路径 [英] Bash script absolute path with OS X

问题描述

我正在尝试获取 OS X 上当前正在运行的脚本的绝对路径.

I am trying to obtain the absolute path to the currently running script on OS X.

我看到很多关于 readlink -f $0 的回复.然而，由于 OS X 的 readlink 与 BSD 的相同，它只是不起作用(它适用于 GNU 的版本).

I saw many replies going for readlink -f $0. However since OS X's readlink is the same as BSD's, it just doesn't work (it works with GNU's version).

是否有现成的解决方案?

Is there an out-of-the-box solution to this?

推荐答案

有一个 realpath() C 函数可以完成这项工作，但我没有在命令中看到任何可用的东西-线.这是一个快速而肮脏的替代品:

There's a realpath() C function that'll do the job, but I'm not seeing anything available on the command-line. Here's a quick and dirty replacement:

#!/bin/bash

realpath() {
    [[ $1 = /* ]] && echo "$1" || echo "$PWD/${1#./}"
}

realpath "$0"

如果路径以 / 开头，则逐字打印路径.如果不是，它必须是一个相对路径，所以它在前面加上 $PWD.#./ 部分将 ./ 从 $1 的前面去掉.

This prints the path verbatim if it begins with a /. If not it must be a relative path, so it prepends $PWD to the front. The #./ part strips off ./ from the front of $1.

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