以编程方式从Mac OS X获取处理器详细信息 [英] Programmatically get processor details from Mac OS X

问题描述

我在Mac OS X上运行的应用程序，需要检索有关其所运行的计算机的详细信息以报告系统信息.我需要的项目之一是有关计算机中安装的处理器的详细信息.

My application running on Mac OS X that needs to retrieve details about the machine it is running on to report for system information. One of the items I need is details about the processor(s) installed in the computer.

我的代码当前可以运行，但远非理想的解决方案，实际上我认为这是一个糟糕的解决方案，但是我没有运气来找到更好的解决方案.

My code currently works, but is far from an ideal solution, in fact I consider it a bad solution, but I have had no luck in finding a better one.

我当前报告的信息以及经过某种格式设置后的信息如下:

The information I report currently and after some formatting looks like:

处理器:Intel Core 2 Duo 2.1 GHz，Family 6 Model 23 Stepping 6

Processor: Intel Core 2 Duo 2.1 GHz, Family 6 Model 23 Stepping 6

我获得的所有信息都是通过从popen()调用的命令行实用程序获得的.处理器描述的可读部分来自"system_profiler"命令输出，而族"，模型"和步进"值则来自"sysctl"命令.

All of the info I get is through command-line utilities called from a popen(). The readable part of the processor description is taken from the "system_profiler" command output and the Family, Model, and Stepping values are taken from the "sysctl" command.

这些命令行实用程序必须从某处获取信息. 我想知道是否有可用的编程界面来获取相同的信息?

These command-line utilities must be getting there information from somewhere. I'm wondering if there is an programmatic interface available to get this same info?

相关:

• 如何在Mac?

推荐答案

使用sysctlbyname而不是sysctl，例如

#include <stdio.h>
#include <stdint.h>
#include <sys/types.h>
#include <sys/sysctl.h>

uint64_t get_cpu_freq(void)
{
    uint64_t freq = 0;
    size_t size = sizeof(freq);

    if (sysctlbyname("hw.cpufrequency", &freq, &size, NULL, 0) < 0)
    {
        perror("sysctl");
    }
    return freq;
}

通过从命令行查看sysctl -a的输出，可以获得可以传递给systctlbyname的名称的列表.

You can get a list of the names that can be passed to systctlbyname by looking at the output of sysctl -a from the command line.

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