Makefile中的条件语句:缺少分隔符错误? [英] Conditionals in Makefile: missing separator error?

问题描述

我要按照 http://sunsite.ualberta.ca/Documentation/Gnu/make-3.79/html_chapter/make_7.html#SEC72 .但是，我得到了错误Makefile:219: *** missing separator. Stop.，其中第219行是带有ifeq语句的行. -$(FC)的三行确实以制表符开头.

I want to write some conditionals in a Makefile, following the guide at http://sunsite.ualberta.ca/Documentation/Gnu/make-3.79/html_chapter/make_7.html#SEC72. However, I get the error Makefile:219: *** missing separator. Stop., where line 219 is the line with the ifeq statement. The three lines with the -$(FC) do start with a tab.

我正在使用GNU Make 3.81.任何帮助，我们将不胜感激！

I'm using GNU Make 3.81. Any help is greatly appreciated!

[...]

mod: $(MODBIN)

$(MODBIN): $(MODSRC)
ifeq($(FC),gfortran)
    -$(FC) $(MODFLAGS) -J$(INCPATH) $(INCLUDE) -c -o $@ $(subst $(BUILDPATH),$(MODPATH),$*).f90 $(NETCDFLDFLAGS)
else ifeq($(FC),ifort)
    -$(FC) $(MODFLAGS) -module $(INCPATH) $(INCLUDE) -c -o $@ $(subst $(BUILDPATH),$(MODPATH),$*).f90 $(NETCDFLDFLAGS)
else ifeq ($(FC),xlf2003_r)
    -$(FC) $(MODFLAGS) -qmoddir=$(INCPATH) $(INCLUDE) -c -o $@ $(subst $(BUILDPATH),$(MODPATH),$*).f90 $(NETCDFLDFLAGS)
endif

io: $(IOBIN)

[...]

根据@ sagar-sakre的建议，我更改为:

Following the advice by @sagar-sakre, I changed to this:

[...]
mod: $(MODBIN)

$(MODBIN): $(MODSRC)
    ifeq($(B3dC),gfortran)
    -$(FC) $(MODFLAGS) -J$(INCPATH) $(INCLUDE) -c -o $@ $(subst $(BUILDPATH),$(MODPATH),$*).f90 $(NETCDFLDFLAGS)
    else ifeq($(B3dC),ifort)
    -$(FC) $(MODFLAGS) -module $(INCPATH) $(INCLUDE) -c -o $@ $(subst $(BUILDPATH),$(MODPATH),$*).f90 $(NETCDFLDFLAGS)
    else ifeq ($(B3dC),xlf2003_r)
    -$(FC) $(MODFLAGS) -qmoddir=$(INCPATH) $(INCLUDE) -c -o $@ $(subst $(BUILDPATH),$(MODPATH),$*).f90 $(NETCDFLDFLAGS)
    endif endif endif

io: $(IOBIN)
[...]

但是，现在出现此错误:

However, now I get this error:

ifeq(xlf,gfortran)
/bin/sh: -c: line 0: syntax error near unexpected token `xlf,gfortran'
/bin/sh: -c: line 0: `ifeq(xlf,gfortran)'
make: *** [build/basic.o] Error 2

所以这里还是有问题...

So still something's wrong here ...

推荐答案

ifeq后应该有一个[空格]

There should be a [space] after ifeq

mod: $(MODBIN)
$(MODBIN): $(MODSRC)
ifeq ($(FC),gfortran)
    -$(FC) $(MODFLAGS) -J$(INCPATH) $(INCLUDE) -c -o $@ $(subst
    $(BUILDPATH),$(MODPATH),$*).f90 $(NETCDFLDFLAGS)
else ifeq ($(FC),ifort)
    -$(FC) $(MODFLAGS) -module $(INCPATH) $(INCLUDE) -c -o $@ $(subst
    $(BUILDPATH),$(MODPATH),$*).f90 $(NETCDFLDFLAGS)
else ifeq ($(FC),xlf2003_r)
     -$(FC) $(MODFLAGS) -qmoddir=$(INCPATH) $(INCLUDE) -c -o $@ $(subst 
     $(BUILDPATH),$(MODPATH),$*).f90 $(NETCDFLDFLAGS)
endif

常规Makefile为

General Makefile would be

target:dependencies
ifeq ( parm1, parm2)
 [TAB]   operation
else
 [TAB]   operation
endif

这篇关于Makefile中的条件语句:缺少分隔符错误?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！