makefile:缺少分隔符 [英] makefile : missing separator

问题描述

#kernel build system and can use its lanauge
ifneq($(KERNELRELEASE),)
 obj-m:=helloworld.o
else
 KDIR:= /lib/modules/2.6.33.3-85.fc13.i686/build
all:
 make -C $(KDIR) M=$(PWD) modules
clean:
 rm -f *.ko *.o *.mod.o *.mod.c *.symvers
endif

错误是:

makefile:2:***缺少分隔符.停止

但是对于ifneq($(KERNELRELEASE),)，如果我之前添加了标签页，则会收到另一个错误:

makefile:2:***命令在第一个目标之前开始.停止

解决方案

ifneq和(之间必须有一个空格.

TAB前缀意味着它是一个Shell命令，因此请确保Shell命令(make和rm)以TAB开头，而所有其他行(例如ifneq)都不以TAB开头. /p>

#kernel build system and can use its lanauge
ifneq($(KERNELRELEASE),)
 obj-m:=helloworld.o
else
 KDIR:= /lib/modules/2.6.33.3-85.fc13.i686/build
all:
 make -C $(KDIR) M=$(PWD) modules
clean:
 rm -f *.ko *.o *.mod.o *.mod.c *.symvers
endif

The error is:

makefile:2:*** missing separator . stop

but for the ifneq($(KERNELRELEASE),), if I add a tab before, I get another error:

makefile:2: ***commands commence before first target. stop

解决方案

There must be a space between ifneq and (.

The TAB prefix means that it is a shell command, so be sure that the shell commands (make and rm) begin with TAB, and all other lines such as ifneq do not begin with TAB.

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