Makefile顺序执行 [英] Makefile sequential execution

问题描述

我有以下Makefile:

I have the following Makefile:

all: generate print # <-- doesn't work

date: 
    date > date.txt

ls:
    ls -la > ls.txt

generate: ls date

print: *.txt
    cat $^

clean:
    rm *.txt

目标 date 和 ls 分别生成一个文件，目标 print 将其打印出来.

The targets date and ls generate a file each, the target print, prints them out.

如何编写目标 all ，以便它先 生成文件，然后然后打印?

How do I write the target all, so that it first generates the files and then prints it?

推荐答案

只需添加管道符号:

all: | generate print

从制作手册:

可以通过在先决条件列表中放置管道符号(|)来指定

仅订购的先决条件.右侧的所有先决条件都是仅可订购的:

Order-only prerequisites can be specified by placing a pipe symbol (|) in the prerequisites list: any prerequisites to the left of the pipe symbol are normal; any prerequisites to the right are order-only:

targets : normal-prerequisites | order-only-prerequisites

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