如何在Python中从列表的dict中的值生成所有组合 [英] How to generate all combination from values in dict of lists in Python

问题描述

我想生成在dict中索引的列表中的值的所有组合:

I would like to generate all combinations of values which are in lists indexed in a dict:

{'A':['D','E'],'B':['F','G','H'],'C':['I','J']}

每次，每个dict条目中的一项都会被选中，并与其他键中的项组合在一起，所以我有:

Each time, one item of each dict entry would be picked and combined to items from other keys, so I have:

['D','F','I']
['D','F','J']
['D','G','I']
['D','G','J']
['D','H','I']
...
['E','H','J']

我知道在itertools中有一些东西可以生成列表中项目的组合，但是我不认为我可以在这里使用它，因为我有不同的值池".

I know there is a something to generate combinations of items in list in itertools but I don't think I can use it here since I have different "pools" of values.

是否有任何现有的解决方案可以执行此操作，或者我应该如何继续执行此操作，我对这种嵌套结构还是很满意.

Is there any existing solution to do this, or how should I proceed to do it myself, I am quite stuck with this nested structure.

推荐答案

import itertools as it

my_dict={'A':['D','E'],'B':['F','G','H'],'C':['I','J']}
allNames = sorted(my_dict)
combinations = it.product(*(my_dict[Name] for Name in allNames))
print(list(combinations))

哪些印刷品:

[('D', 'F', 'I'), ('D', 'F', 'J'), ('D', 'G', 'I'), ('D', 'G', 'J'), ('D', 'H', 'I'), ('D', 'H', 'J'), ('E', 'F', 'I'), ('E', 'F', 'J'), ('E', 'G', 'I'), ('E', 'G', 'J'), ('E', 'H', 'I'), ('E', 'H', 'J')]

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