Python-尝试通过for循环创建字典 [英] Python - Trying to create a dictionary through a for loop

问题描述

我试图通过使用for循环来创建字典.我有一个有序列表，并且我试图将列表中的值与有序列号进行匹配.例如: {0:100， 1:423， 2:434}

I am trying to create a dictionary by using a for loop. I have an ordered list, and I am trying to match up the values from the list to ordered numbers. For Example: {0: 100, 1: 423, 2: 434}

我只是在制作for循环时遇到麻烦.

I am just having trouble making the for loop.

list = [102, 232, 424]
count = 0
d = {} #Empty dictionary to add values into

for i in list:
    #dictionary key = count
    #key.append(i)
    count+=1

因此，在for循环中，我本质上是想让count变量成为键，并将列表中的对应项作为值.然后，我将添加一个数，然后继续.如果我的代码在for循环中有点不清楚，我也很抱歉.那不是实际的代码，而只是我所寻找的一般性想法.谁能帮我?谢谢.

So in the for loop I essentially want to make the count variable the key, and have the corresponding item in the list as the value. Then I would add one to count, and continue. Also I am sorry if my code is a little unclear in the for loop. That isn't actual code, but is just a general idea of what I was looking for. Can anyone help me? Thank you.

推荐答案

您可以通过执行dictionary[key] = item在字典中设置项目，因此您可以这样做:

You set an item in a dictionary by doing dictionary[key] = item, so in your case you would do:

list = [102, 232, 424]
count = 0
d = {} #Empty dictionary to add values into

for i in list:
    d[count] = i
    count+=1

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