四元数"lookAt"功能 [英] Quaternion "lookAt" function

问题描述

我正在努力解决以下问题.我正在使用骨骼动画，所以我希望玩家的头部跟随空间中的另一个对象.我的上轴是+ Z，前轴是+ Y，四元数的大小以W为单位.我尝试对gluLookAt使用mesa代码，并使用3x3矩阵转换为四元数，但是它不能按预期工作所以我走了另一个方向...

Im struggling with the following problem. Im working with bone animation and I want (ie) the head of the player to follow an another object in space. My up axis is +Z my forward axis is +Y, and the magnitude of the quaternion is in W. I tried to use the mesa code for gluLookAt and use the 3x3 matrix to transform to a quaternion but it doesn't work as expected so I go in another direction...

到目前为止，我获得了以下代码，该代码几乎"在至少播放器的头部朝着正确方向旋转(但是X角度似乎影响Y旋转轴)的情况下起作用，但是在跟随时却朝上看地板上约65度的物体:

So far I got the following code that is "almost" working at least the head of the player is rotating (however the X angle seems to affect the Y rotation axis) in the good direction but its looking straight up instead on following an object on the floor at about 65 degree:

qt LookRotation( v3 lookAt, v3 upDirection )
{
qt t;

v3 forward = lookAt;
v3 up = upDirection;

OrthoNormalize( &forward, &up );

v3 right = v3_cross( up, forward );

mat3 m = mat3_make( right.x, up.x, forward.x,
                    right.y, up.y, forward.y,
                    right.z, up.z, forward.z );

t.w = sqrtf( 1.0f +
             m.r[ 0 ].x +
             m.r[ 1 ].y +
             m.r[ 2 ].z ) * 0.5f;

float w4_recip = 1.0f / ( 4.0f * t.w );

t.x = ( m.r[ 2 ].y - m.r[ 1 ].z ) * w4_recip;

t.y = ( m.r[ 0 ].z - m.r[ 2 ].x ) * w4_recip;

t.z = ( m.r[ 1 ].x - m.r[ 0 ].y ) * w4_recip;

t = qt_normalize( t );

return t;
}

... ... ...

... ... ...

v3 v = v3_sub( vec4_to_v3( transform.world.r[ 3 ] /* The object XYZ location in the world */),
           skeleton->final_pose.location[ i ] /* i = The head joint location */ );

v = v3_normalize( v );

qt q = LookRotation( v,
        v3_make( 0.0f, 0.0f, 1.0f ) );

有人可以帮我解决这个问题吗?我有点像四元数，但我真的不知道我该在哪里搞砸.经过大量研究后，基本上我想做的是类似Unity API的事情: http: //docs.unity3d.com/Documentation/ScriptReference/Quaternion.LookRotation.html

Can someone help me figuring out this problem... Im kinda new with quaternions and don't really know where I could have messed up. After quite some research basically what I want to do is something like the Unity API: http://docs.unity3d.com/Documentation/ScriptReference/Quaternion.LookRotation.html

推荐答案

我认为此功能将满足您的需求:

I think this function will do what you need:

/// <summary>
/// Evaluates a rotation needed to be applied to an object positioned at sourcePoint to face destPoint
/// </summary>
/// <param name="sourcePoint">Coordinates of source point</param>
/// <param name="destPoint">Coordinates of destionation point</param>
/// <returns></returns>
public static Quaternion LookAt(Vector3 sourcePoint, Vector3 destPoint)
{
    Vector3 forwardVector = Vector3.Normalize(destPoint - sourcePoint);

    float dot = Vector3.Dot(Vector3.forward, forwardVector);

    if (Math.Abs(dot - (-1.0f)) < 0.000001f)
    {
        return new Quaternion(Vector3.up.x, Vector3.up.y, Vector3.up.z, 3.1415926535897932f);
    }
    if (Math.Abs(dot - (1.0f)) < 0.000001f)
    {
        return Quaternion.identity;
    }

    float rotAngle = (float)Math.Acos(dot);
    Vector3 rotAxis = Vector3.Cross(Vector3.forward, forwardVector);
    rotAxis = Vector3.Normalize(rotAxis);
    return CreateFromAxisAngle(rotAxis, rotAngle);
}

// just in case you need that function also
public static Quaternion CreateFromAxisAngle(Vector3 axis, float angle)
{
    float halfAngle = angle * .5f;
    float s = (float)System.Math.Sin(halfAngle);
    Quaternion q;
    q.x = axis.x * s;
    q.y = axis.y * s;
    q.z = axis.z * s;
    q.w = (float)System.Math.Cos(halfAngle);
    return q;
}

此代码来自此处: https://gamedev.stackexchange.com/questions/15070/orienting-一个模型面对一个目标 我只是对其稍作修改以适合我的情况，这是在不使用Unity3D的情况下实现了transform.LookAt.

This code comes from here: https://gamedev.stackexchange.com/questions/15070/orienting-a-model-to-face-a-target I just slightly modified it to fit my case, which was implementation of the transform.LookAt without using Unity3D.

这篇关于四元数"lookAt"功能的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！