在Python中使用Sin-1或反正弦 [英] Using Sin-1 or inverse sin in python

问题描述

这是我的代码:

# point of intersection between opposite and hypotenuse

x,y  =    pygame.mouse.get_pos()


# using formula for length of line

lenline1 = (x-x)**2 + (300-y)**2
lenline2 = (x-700)**2 + (y-300)**2

opposite = math.sqrt(lenline1)

adjacent = math.sqrt(lenline2)

# Converting length of lines to angle

PQ = opposite/adjacent
k = math.sin(PQ)
j = math.asin(k)

print(j)  

我没有得到我期望的结果，尽管在弄乱它之后我已经接近了，但并不完全正确.有人可以告诉我我做错了什么.我有两行: 对面和相邻 我希望用罪的逆来获得角度.我究竟做错了什么.我只是一个初学者，所以请不要提供太多详细信息.我无法想象这很难做到.

I'm not getting the results I expected, although after messing around with it I got close but it wasn't quite right. Could someone please tell me what I'm doin wrong. I have two lines: opposite and adjacent And I wish to get the angle using the inverse of sin. What am I doing wrong. I'm only a beginner so don't give too detailed info. I can't imagine this is hard to do.

谢谢.

推荐答案

要找到两条线之间的角度，请使用以下关系:

To find the angle between two lines, use the following relation:

cos(angle) = (l1 dot l2) / (|l1| |l2|)

也就是说，

dotproduct = l1x * l2x + l1y * l2y
lenproduct = |l1| * |l2|
angle = acos(dotproduct / lenproduct)

其中l1x，l1y是线l1的x，y分量.

where l1x, l1y are the x,y components of the line l1.

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