PHP-如果数字可以被3和5整除，则回显 [英] PHP - If number is divisible by 3 and 5 then echo

问题描述

我是PHP的新手，它试图创建以下内容，同时最大程度地减少所需的代码量. PHP应该显示一个100的列表，然后如果数字是/乘3、5或3和5，则显示.如果没有，则不显示任何内容.

I'm new to PHP and trying to create the following whilst minimizing the amount of code needed. PHP should show a list of 100 then display if the number is / by 3, 5 or 3 and 5. If not by any then show nothing.

这是我到目前为止所能获得的，但是任何帮助都将是非常有用的，因为不确定3位和5位的/，如下所示.

This is what I've got so far, but any help would be great since not sure about the / by 3 and 5 bit as you can see below.

<?php $var = range(0, 100); ?>
  <table>
<?php foreach ($var as &$number) {
 echo " <tr>
    <td>$number</td>
    <td>";

    if($number % 3 == 0)  {
    echo "BY3";
} elseif ($number % 5 == 0) {
    echo "BY5";
} elseif ($number % 3 and 5 == 0) {
        echo "BY3 AND 5";
}
 echo "</td></tr>";
}
?>

  </table>

谢谢

推荐答案

不...您应该先检查它是否可分割为15(3x5)(或3和5)，然后再进行其他检查:

Nope... you should check first if it's divisble for 15 (3x5) (or 3 and 5) and after you can do other checks:

if($number % 15 == 0)  {
    echo "BY3 AND 5";
} elseif ($number % 5 == 0) {
    echo "BY5";
} elseif ($number % 3 == 0) {
    echo "BY3";
}
 echo "</td></tr>";

?>

因为每个数字15的整数也将3和5的整数除.所以您的最后一张支票永远都不会打

Because every number divisble for 15 is also divisble for 3 and 5. So your last check could never hit

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