逻辑检查数字是否可以被3整除? [英] Logic to check the number is divisible by 3 or not?

问题描述

不使用％，/或*，我必须找到编号.可以被3整除吗?

without using %, / or * , I have to find the no. is divisible by 3 or not?

可能是面试问题.

谢谢.

推荐答案

减去3直到您选择其中一个

Subtract 3 until you either

点击0-数字可被3(或)整除

hit 0 - number was divisible by 3 (or)

获取小于0的数字-数字不可除

get a number less than 0 - number wasn't divisible

 if (number > 0)
 {
        while (number > 0)
        {
            number -= 3;
    }
}
else if( number < 0)
{
    while number < 0:
        number += 3
}
return number == 0

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