C ++中两个圆的交点 [英] Intersection points of two circles in c++

问题描述

我想在c ++中找到两个小峰的相交点.我有两个圆的中心和半径.谁能帮我吗??

I want to find the Intersection point of two cricles in c++ .I have the center and radius of the two circles. can anyone help me ??

推荐答案

假设您有一个圆心，并且它是半径 您可以设置

Assuming you have a circles center and it's radius you can setup an equation like

(x-x1)²+(y-y1)²=r1²

您可以对两个圈子都这样做

you can do this for both circles

I  x²-2xx1+x1²+y²-yy1+y1²=r1²
II x²-2xx2+x2²+y²-yy2+y2²=r2²

然后您可以在I中插入II，然后就可以了:)

then you can insert II in I and there you go :)

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