有时间限制的数学测验(同时功能)-高级python [英] math quiz with a time limit (simultaneous functions) - advanced python

问题描述

所以我想运行两个程序，一个计时器和一个数学问题.但总是输入似乎正在停止计时器功能，甚至根本不运行计时器.有什么办法可以解决这个问题? 我将保持示例简单.

So I would like to run two programs, a timer and a math question. But always the input seems to be stopping the timer funtion or not even run at all. Is there any ways for it to get around that? I'll keep the example simple.

import time

start_time = time.time()
timer=0
correct = answer
answer = input("9 + 9 = ") 
#technically a math question here
#so here until i enter the input prevents computer reading the code
while True:
    timer = time.time() - start_time
    if timer > 3:
#3 seconds is the limit
    print('Wrong!')
quit()

回顾一下，我希望玩家在3秒内回答问题.

So recap i would like the player to answer the question in less than 3 seconds.

3秒后，游戏将打印错误并退出

after the 3 seconds the game will print wrong and exit

如果玩家在三秒钟内回答，则计时器将被终止"或停止，然后触发错误"并退出

if the player answer within three seconds the timer would be 'terminated' or stopped before it triggers 'wrong' and quit

希望您能理解，并非常感谢您的帮助

hope you understand, and really appreciate your help

推荐答案

在Windows上，您可以使用代码示例进行了现代化 ):

On Windows you can use the msvcrt module's kbhit and getch functions (I modernized this code example a little bit):

import sys
import time
import msvcrt


def read_input(caption, timeout=5):
    start_time = time.time()
    print(caption)
    inpt = ''
    while True:
        if msvcrt.kbhit():  # Check if a key press is waiting.
            # Check which key was pressed and turn it into a unicode string.
            char = msvcrt.getche().decode(encoding='utf-8')
            # If enter was pressed, return the inpt.
            if char in ('\n', '\r'): # enter key
                return inpt
            # If another key was pressed, concatenate with previous chars.
            elif char >= ' ': # Keys greater or equal to space key.
                inpt += char
        # If time is up, return the inpt.
        if time.time()-start_time > timeout:
            print('\nTime is up.')
            return inpt

# and some examples of usage
ans = read_input('Please type a name', timeout=4)
print('The name is {}'.format(ans))
ans = read_input('Please enter a number', timeout=3)
print('The number is {}'.format(ans))

我不确定您在其他操作系统上到底要做什么(研究 termios ，tty，选择).

I'm not sure what exactly you have to do on other operating systems (research termios, tty, select).

另一种可能性是 curses 模块也具有getch功能，您可以将其设置为nodelay(1)(非阻塞)，但是对于Windows，您首先必须从

Another possibility would be the curses module which has a getch function as well and you can set it to nodelay(1) (non-blocking), but for Windows you first have to download curses from Christopher Gohlke's website.

import time
import curses


def main(stdscr):
    curses.noecho()  # Now curses doesn't display the pressed key anymore.
    stdscr.nodelay(1)  # Makes the `getch` method non-blocking.
    stdscr.scrollok(True)  # When bottom of screen is reached scroll the window.
    # We use `addstr` instead of `print`.
    stdscr.addstr('Press "q" to exit...\n')
    # Tuples of question and answer.
    question_list = [('4 + 5 = ', '9'), ('7 - 4 = ', '3')]
    question_index = 0
    # Unpack the first question-answer tuple.
    question, correct_answer = question_list[question_index]
    stdscr.addstr(question)  # Display the question.

    answer = ''  # Here we store the current answer of the user.
    # A set of numbers to check if the user has entered a number.
    # We have to convert the number strings to ordinals, because
    # that's what `getch` returns.
    numbers = {ord(str(n)) for n in range(10)}

    start_time = time.time()  # Start the timer.

    while True:
        timer = time.time() - start_time

        inpt = stdscr.getch()  # Here we get the pressed key.
        if inpt == ord('q'):  # 'q' quits the game.
            break
        if inpt in numbers:
            answer += chr(inpt)
            stdscr.addstr(chr(inpt), curses.A_BOLD)
        if inpt in (ord('\n'), ord('\r')):  # Enter pressed.
            if answer == correct_answer:
                stdscr.addstr('\nCorrect\n', curses.A_BOLD)
            else:
                stdscr.addstr('\nWrong\n', curses.A_BOLD)

        if timer > 3:
            stdscr.addstr('\nToo late. Next question.\n')

        if timer > 3 or inpt in (ord('\n'), ord('\r')):
            # Time is up or enter was pressed; reset and show next question.
            answer = ''
            start_time = time.time()  # Reset the timer.
            question_index += 1
            # Keep question index in the correct range.
            question_index %= len(question_list)
            question, correct_answer = question_list[question_index]
            stdscr.addstr(question)

# We use wrapper to start the program.
# It handles exceptions and resets the terminal after the game.
curses.wrapper(main)

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