从MATLAB数据采集的问题 [英] problems with data acquisition from MATLAB
问题描述
我以前寻求帮助来读取文本数据C程序(一个Exe)生成的文件.
I previously asked for help in reading data from a text file generated by a C program (an Exe).
使用 @second 的解决方案,我解决了这个问题,但是昨天我发现输出文件比我预期的要复杂.
Using @second's solution, I solved the problem but yesterday I discovered that the output file is more complex than I had expected.
文件输出为:
V|0|0|0|t|0|1|1|4|11|T4|H13||||||||||||
P|40|0.01|10|1|1|0|40|1|1|1||1|*||0|0|0
*|A1|A1|A7|A16|F|F|F|F|F|F|||||||||||||
*|codserv|area|codice|nome|tnom|tmin|tmax|pc|qc|susc|||||||
*|||||kV|kV|kV|MW|MVAR|S||||||||||||
N|I|1|N01|N01|132|125.4|138.6|0|0||||||||
N|I|1|N02|N02|20|19|21|0|0|||||||||||||
N|I|1|N03|N03|20|19|21|1.013532234|0.49087611||||||||
N|I|1|N04|N04|20|19|21|0.390791617|0.189269056||||||||
N|I|1|N05|N05|20|19|21|0.180634542|0.121387171||||||||
N|I|1|N06|N06|20|19|21|0.709472564|0.343613323||||||||
N|I|1|N07|N07|20|19|21|0.103495727|0.069549543||||||||
N|I|1|N08|N08|20|19|21|0.351712456|0.170342158||||||||
N|I|1|N09|N09|20|19|21|0.097697904|0.06565339||||||||
N|I|1|N10|N10|20|19|21|0.162165157|0.078540184||||||||
N|I|1|N11|N11|20|19|21|0|0||||||||
*|A1|A8|A7|A7|F|F|F|F||F||F
*|plev|area|codice|estr1|estr2|lung|imax|rsd|xsd|bsd1|bsd2|||
*|||||km|A|Ohm|Ohm||S||S
L|I|D10203|N02|N03|1.884|360|0.41071|0.207886957|3.19E-08|3.19E-08|||||||||||||
L|I|D10304|N03|N04|1.62|360|0.35316|0.1787563|3.19E-08|3.19E-08|||||||||||||
L|I|D10405|N04|N05|0.532|360|0.11598|0.058702686|3.19E-08|3.19E-08|||||||||||||
L|I|D10506|N05|N06|1.284|360|0.27991|0.14168092|3.19E-08|3.19E-08|||||||||||||
L|I|D10607|N06|N07|1.618|280|0.53879|0.194766124|3.00E-08|3.00E-08|||||||||||||
L|I|D10708|N07|N08|0.532|280|0.17716|0.064039294|3.00E-08|3.00E-08|||||||||||||
L|I|D10809|N08|N09|2|360|0.436|0.220686791|3.19E-08|3.19E-08|||||||||||||
L|I|D10910|N09|N10|2.4|360|0.5232|0.264824149|3.19E-08|3.19E-08||||||||||||
*|A1|A8|A7|A7|F|F|A1|F|F|F|F|F|F||F||F|||||||||||||||||||||||||
*|codserv|codice|estr1|estr2|vn1|vn2|nod1|varp|varm|np|Pb|rsd|xsd||bsd1||bsd2||||||||||||
*|||||kV|kV||%|%||MVA|%|%||%||%|||||
%%%%%------%%%%%------%%%% **(read up to here)**
other unnecessary data
算法应:
- 跳过前3行
-
跳过第五行
- skip the first 3 rows
skip fifth row
对于第四行*|codserv|area|codice|nome|tnom|tmin|tmax|pc|qc|susc|||||||
,将每个字符串保存在向量为空的codeserv=[] area=[] codice=[] nome=[] tnom=[] tmin=[] tmax=[] pc=[] qc=[] susc=[]
For the fourth row *|codserv|area|codice|nome|tnom|tmin|tmax|pc|qc|susc|||||||
, save each string in a vector empty codeserv=[] area=[] codice=[] nome=[] tnom=[] tmin=[] tmax=[] pc=[] qc=[] susc=[]
在向量的第四行之后填充向量和字符串的向量
Fill vectors with data and strings in the rows following the fourth
codeserv=[N N N N N N N N N N ....]
area=[I I I I I I I ....]
codice=[1 1 1 1 1 1 ...]
nome=[N01 N02 N03 N04 N05 ]
tnom=[N01 N02 N03 N04 N05]
tmin=[132 20 20.....]
tmax=[125.4 19 19 19 ....]
pc=[138.6 21 21 21....]
qc=[0 0 1.013532234 ....]
susc=[0 0 0.49087611]
对以字母L
开头的数据执行相同的操作.阅读此行codice|estr1|estr2|lung|imax|rsd|xsd||bsd1||bsd2
,并用L
Do the same with the data starting with the letter L
. Read this line codice|estr1|estr2|lung|imax|rsd|xsd||bsd1||bsd2
and fill the vectors with values in the lines beginning with L
plev=[L L L L L L L ....]
area=[I I I I I I I ....]
codice=[D10203 D10304 ...]
estr1=[N02 N03 N04 N05 ...]
estr2=[N03 N04 N05...]
lung=[1.884 1,662 ....]
imax=[360 360 .....]
rsd=[number....]
xsd=[number....]
bsd1=[number ....]
bsd2=[number....]
我试图改写上一个问题中的代码,但是鉴于以N
和L
开头的行不知道我需要多少行才能读取第一个字符串并计算数字L
是.
I tried to adapt the code from the previous question, but given that the lines that start with N
and L
do not know how many I need to know how to read the first string and count the number N
and L
are.
read
[vp***NNNNNNNNNNNNNNNNNNNNNNNNLLLLLLLLLLLLLLLLLLLLL***]
length N
length L
skip 1 2 3 line
read 4 line, create vector
codeserv=[N N N N N N N N N N ....]
area=[I I I I I I I ....]
codice=[1 1 1 1 1 1 ...]
nome=[N01 N02 N03 N04 N05 ]
tnom=[N01 N02 N03 N04 N05]
tmin=[132 20 20.....]
tmax=[125.4 19 19 19 ....]
pc=[138.6 21 21 21....]
qc=[0 0 1.013532234 ....]
susc=[0 0 0.49087611]
skip length N +1 line
read *|plev|area|codice|estr1|estr2|lung|imax|rsd|xsd|bsd1|bsd2|||
skip length N +3 line
create
plev=[L L L L L L L ....]
area=[I I I I I I I ....]
codice=[D10203 D10304 ...]
estr1=[N02 N03 N04 N05 ...]
estr2=[N03 N04 N05...]
lung=[1.884 1,662 ....]
imax=[360 360 .....]
rsd=[number....]
xsd=[number....]
bsd1=[number ....]
bsd2=[number....]
close the cycle
我希望这是可以理解的.我最大的问题是计算文本中的N
和L
.
I hope it is understandable. My biggest problem is counting the N
and L
in the text.
推荐答案
function readtest2()
fid = fopen('test2.txt');
skipLines(3)
names1 = getNames;
skipLines(1);
nEntries1 = countPrefix('N');
data1 = textscan(fid,'%s %s %d %s %s %d %d %f %f %f %[| ]', nEntries1, 'delimiter','|');
skipLines(2)
names2 = getNames;
skipLines(1);
nEntries2 = countPrefix('L');
data2 = textscan(fid,'%s %s %s %s %s %f %d %f %f %f %f %[| ]', nEntries2, 'delimiter','|');
fclose(fid);
getData(data1, names1);
getData(data2, names2);
function names = getNames()
names = fgetl(fid);
names = textscan(names,'%s','delimiter','|');
end
function getData(data, names)
for i = 1:size(data,2)-1
values = ( data{i}(1:end));
if(iscell(values))
values = cell2mat(values);
end
name = names{1}{i+1};
% very basic error checking
if(~strcmp(name, ''))
%save the value in the calling work space
assignin('base', name, values)
end
end
end
function skipLines(n)
while(n > 0)
fgetl(fid);
n = n - 1;
end
end
function n = countPrefix(prefix)
pos = ftell(fid);
n = 0;
currLine = fgetl(fid);
while(currLine(1) == prefix)
currLine = fgetl(fid);
n = n + 1;
end
fseek(fid, pos, 'bof');
end
end
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