使用字典使用matplotlib绘制条形图 [英] Plot a bar using matplotlib using a dictionary
本文介绍了使用字典使用matplotlib绘制条形图的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
是否可以使用直接使用字典数据的matplotlib
绘制条形图?
Is there any way to plot a bar plot using matplotlib
using data directly from a dict?
我的字典像这样:
D = {u'Label1':26, u'Label2': 17, u'Label3':30}
我期待着
fig = plt.figure(figsize=(5.5,3),dpi=300)
ax = fig.add_subplot(111)
bar = ax.bar(D,range(1,len(D)+1,1),0.5)
正常工作,但没有成功.
to work, but it does not.
这是错误:
>>> ax.bar(D,range(1,len(D)+1,1),0.5)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/local/lib/python2.7/site-packages/matplotlib/axes.py", line 4904, in bar
self.add_patch(r)
File "/usr/local/lib/python2.7/site-packages/matplotlib/axes.py", line 1570, in add_patch
self._update_patch_limits(p)
File "/usr/local/lib/python2.7/site-packages/matplotlib/axes.py", line 1588, in _update_patch_limits
xys = patch.get_patch_transform().transform(vertices)
File "/usr/local/lib/python2.7/site-packages/matplotlib/patches.py", line 580, in get_patch_transform
self._update_patch_transform()
File "/usr/local/lib/python2.7/site-packages/matplotlib/patches.py", line 576, in _update_patch_transform
bbox = transforms.Bbox.from_bounds(x, y, width, height)
File "/usr/local/lib/python2.7/site-packages/matplotlib/transforms.py", line 786, in from_bounds
return Bbox.from_extents(x0, y0, x0 + width, y0 + height)
TypeError: coercing to Unicode: need string or buffer, float found
推荐答案
您可以通过先绘制条形图然后设置适当的刻度来分两行完成:
You can do it in two lines by first plotting the bar chart and then setting the appropriate ticks:
import matplotlib.pyplot as plt
D = {u'Label1':26, u'Label2': 17, u'Label3':30}
plt.bar(range(len(D)), list(D.values()), align='center')
plt.xticks(range(len(D)), list(D.keys()))
# # for python 2.x:
# plt.bar(range(len(D)), D.values(), align='center') # python 2.x
# plt.xticks(range(len(D)), D.keys()) # in python 2.x
plt.show()
请注意,倒数第二行应在python3中读为plt.xticks(range(len(D)), list(D.keys()))
,因为D.keys()
返回一个生成器,而matplotlib无法直接使用该生成器.
Note that the penultimate line should read plt.xticks(range(len(D)), list(D.keys()))
in python3, because D.keys()
returns a generator, which matplotlib cannot use directly.
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