计算后将因子均值获取到数据集中 [英] Getting Factor Means into the dataset after calculation

问题描述

我正在尝试根据各个会议方式和SD为我正在使用的变量创建一个归一化值.我发现使用功能的会议手段:

I am trying to create a normalization value for a variable I am working with based on individual conference means and SDs. I found the conference means using the function:

confavg=aggregate(base$AVG, by=list(base$confName), FUN=mean)

因此，在获得31个会议的均值后，我想返回并为每个参与者输入这些均值，以便我可以轻松地基于会议均值计算归一化因子.

And so after getting the means for the 31 conferences, I want to go back and for each individual player put these means in so I can easily calculate a normalization factor based on the conference mean.

我试图创建大型ifelse或if语句，其中confavg是会议的平均值.

I have tried to create large ifelse or if statements where confavg is the conference average.

ifelse((base$confName=="America East Conference"),confavg[1,2]->base$CAVG,0->base$CAVG)

但没有任何效果.理想情况下，我想带每个玩家说:

but nothing works. Ideally I would want to take every player and say:

Normalization = (player average - conference average)/conference standard deviation

我应该怎么做?

以下是一些示例数据:

AVG = c(.350,.400,.320,.220,.100,.250,.400,.450)
Conf = c("SEC","ACC","SEC","B12","P12","ACC","B12","P12")
Conf=as.factor(Conf)
sampleconfavg=aggregate(AVG, by=list(Conf), FUN=mean)
sampleconfsd=aggregate(AVG, by=list(Conf), FUN=sd)

所以每个玩家都有自己的平均值-会议的平均会议数/标准差

So each player would have their average - the conference average / sd of conference

所以对于第一个家伙，它将是:

so for the first guy it would be:

(.350 - .335) / 0.0212132 = 0.7071069

但是我希望构建一个功能来为数据集中的所有人做到这一点.谢谢！

but I am hoping to build a function that does it for all people in my dataset. Thank you!

edit2:

好的，下面的答案是惊人的，但是(希望)我遇到了最后一个问题.我想基本上对以下三个变量执行此过程:

Alright the answer below is amazing but I am running into (hopefully) one last problem. I want to basically do this process to three variables like:

base3=do.call(rbind, by(base3, base3$confName, FUN=function(x) { x$ScaledAVG <- scale(x$AVG); x}))
base3=do.call(rbind, by(base3, base3$confName, FUN=function(x) { x$ScaledOBP <- scale(x$OBP); x}))
base3=do.call(rbind, by(base3, base3$confName, FUN=function(x) { x$ScaledK.AB <- scale(x$K.AB); x}))

这可以工作，但是当我搜索数据文件时像这样:

Which works but then when I search the datafile like:

base3[((base3$ScaledAVG>2)&(base3$ScaledOBP>2)&(base3$ScaledK.AB<.20)),]

它重置Scaled K.AB值，并且不将其用作搜索参数的一部分.

it resets the Scaled K.AB value and doesn't use it as part of the parameters of the search.

推荐答案

下面是在iris $ Species组中缩放iris $ Sepal.Length的示例:

Here is an example to scale iris$Sepal.Length, within groups of iris$Species:

scaled.iris <- do.call(rbind, 
  by(iris, iris$Species,
     FUN=function(x) { x$Scaled.Sepal.Length <- scale(x$Sepal.Length); x }
  )
)

head(scaled.iris)
##          Sepal.Length Sepal.Width Petal.Length Petal.Width Species Scaled.Sepal.Length
## setosa.1          5.1         3.5          1.4         0.2  setosa          0.26667447
## setosa.2          4.9         3.0          1.4         0.2  setosa         -0.30071802
## setosa.3          4.7         3.2          1.3         0.2  setosa         -0.86811050
## setosa.4          4.6         3.1          1.5         0.2  setosa         -1.15180675
## setosa.5          5.0         3.6          1.4         0.2  setosa         -0.01702177
## setosa.6          5.4         3.9          1.7         0.4  setosa          1.11776320

使用示例数据(仅Conf和AVG):

Using your sample data (Conf and AVG only):

d <- data.frame(Conf, AVG)
dd <- do.call(rbind, by(d, d$Conf, FUN=function(x) { x$Scaled <- scale(x$AVG); x}))

# Remove generated row names
rownames(dd) <- NULL

dd
##   Conf  AVG     Scaled
## 1  ACC 0.40  0.7071068
## 2  ACC 0.25 -0.7071068
## 3  B12 0.22 -0.7071068
## 4  B12 0.40  0.7071068
## 5  P12 0.10 -0.7071068
## 6  P12 0.45  0.7071068
## 7  SEC 0.35  0.7071068
## 8  SEC 0.32 -0.7071068

这篇关于计算后将因子均值获取到数据集中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！