指针地址的含义是什么? [英] What is the meaning of the address of a pointer?

问题描述

如果我们有代码:

int b = 10;
int* a = &b;
std::cout << a << " " << &a << " ";

结果，地址不同.

但是指针的地址是什么意思?

But what's the meaning of address of a pointer?

由于我们的内存中有变量，所以指针具有变量地址的值.但是我们没有将address的值存储在内存中，那么为什么要有一个address的地址呢?

A pointer has the value of a variable's address, since we have a varaible in memory. But we don't have the value of address stored in memory, so why we have the address of an address?

也许我有一些误会，谢谢您的帮助.

Maybe I have some misunderstandings, thank you for your help.

推荐答案

请记住，您机器上的地址本身将是32位或64位值(取决于您的系统体系结构).

Remember an address on your machine is going to be, itself, a 32 or 64-bit value (depending on your system architecture).

在您的示例中，您有一个将值10存储在某个地址中的整数b，我们将其称为地址500

In your example, you have the integer b that stores the value 10 in some address, let's call it address 500

然后您有一个指针a，它存储着500的值，IT拥有自己的地址.

Then you have a pointer a, which stores the value 500, and IT has its own address.

有什么意义?实际上，您可以拥有双指针(或更多指针).

What's the point? You can actually have double-pointers (or more).

您了解

char* string = "hello";

string是一个指向字符数组开头的指针

string is a pointer to the beginning of an array of characters

然后

char** strings;

是指向char *的指针.例如，这就是您可以做一个数组数组的方式.

is a pointer to a char*. That's how you could do an array of arrays, for example.

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