该代码将做什么? (内存管理) [英] What would this code do? (memory management)
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问题描述
char *p = new char[200];
char *p1 = p;
char *p2 = &p[100];
delete [] p1;
这不是测试还是我实际上需要知道的任何东西:)
Btw this is not a test or anything i actually need to know this :)
推荐答案
// allocate memory for 200 chars
// p points to the begining of that
// block
char *p = new char[200];
// we don't know if allocation succeeded or not
// no null-check or exception handling
// **Update:** Mark. Or you use std::no_throw or set_new_handler.
// what happens next is not guranteed
// p1 now points to the same location as p
char *p1 = p;
// another pointer to char which points to the
// 100th character of the array, note that
// this can be treated as a pointer to an array
// for the remaining 100-odd elements
char *p2 = &p[100];
// free the memory for 200 chars
delete [] p1;
// **Update:** Doug. T
// [...] p and p2 are now pointing to freed memory
// and accessing it will be undefined behavior
// depending on the executing environment.
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