在Bukkit插件中以整数形式获取赏金参数 [英] Reading arguments as Integer for a Bounty in a Bukkit plugin

问题描述

这只是插件的开始，还会有更多.这就是我想要的:对于/bounty <name> <amount>，我希望能够读取所读取的内容，以生成类似int a = args[1]的变量，但是我不知道该怎么做.

This is just the start of the plugin and there will be more. This is what I want to have: For /bounty <name> <amount> I want to be able to read what is read on the amount to make a variable like int a = args[1], but I don't know how to do that.

我已经尝试过，但给了我一些错误.我也想要它，所以它只能是命令上的数字.我正在使用bukkit版本:craftbukkit-1.7.10-R0.1-20140804.183445-7

I have tried and it gave me some errors. I also want it so it can only be a number on the command. I am using bukkit version: craftbukkit-1.7.10-R0.1-20140804.183445-7

这是我的代码:

public class Main extends JavaPlugin {

    public void onEnable() {
        Bukkit.getServer().getLogger().info("[Bounty] Enabled");
        Bukkit.getServer().getLogger().info("[Bounty] Developed by ITaco_v2");
    }

    public void onDisable() {
        Bukkit.getServer().getLogger().info("[Bounty] Disabled");
    }

    public boolean onCommand(CommandSender sender, Command cmd, String commandLabel, String[] args) {

        if ( !(sender instanceof Player)) {
            sender.sendMessage(ChatColor.RED + "[" + ChatColor.GREEN + "Bounty" + ChatColor.RED + "] " + ChatColor.GOLD + "In game use only!");
            return true;
        }

        if (cmd.getName().equalsIgnoreCase("bounty")) {
            if (sender.hasPermission("bounty.setbounty"));

            if (args.length == 0) {
                sender.sendMessage(ChatColor.RED + "Please specify a Player and a bounty amount.");
                sender.sendMessage(ChatColor.GREEN + "Like this: /bounty <playername> <amount>");
                return true;

            }

            Player target = Bukkit.getServer().getPlayer(args[0]);

            if (target == null) {
                sender.sendMessage(ChatColor.RED + "Could not find player!");
                return true;
            }

            if (target != null) {
                sender.sendMessage(ChatColor.RED + "Please specify a bounty amount.");
                sender.sendMessage(ChatColor.GREEN + "Like this: /bounty " + args[0] + " <amount>");
                return true;

            }

        }
        return false;
    }

}

推荐答案

在进行实际代码编写之前，您应该查看代码中的以下代码片段:

Before the actual codework, you should review the following code snippets from your code:

if (sender.hasPermission("bounty.setbounty"));
    // This code does nothing, perhaps you meant to return if not true?
if ( !sender.hasPermission("bounty.setbounty"))
    return true;

if (target == null) {
    // ...
}
/* This should be changed to "else"?
 * Or you should actually remove this (if statement),
 * it will never fail as target == null block terminates with "return true;"
 */
if (target != null) {
    // ...
}

---

我将扩展您现有的代码.首先，请确保有第二个参数:

---

I'll extend upon your existing code. Firstly, make sure there is a 2nd argument:

{
    //  }
        if (args.length == 1) sender.sendMessage(NOT_ENOUGH_ARGUMENTS);
        // ...
    }
    return false;
}

然后验证它是否是Integer:

{
    //  }
        if (args.length == 1)
            sender.sendMessage(NOT_ENOUGH_ARGUMENTS);
        else if ( !args[1].matches("-?\\d+"))
            // ** To not allow negative integers, remove '-?' **
            sender.sendMessage(NOT_INTEGER);
    }
    return false;
}

然后用Integer.parseInt()解析它并使用它！

Then parse it with Integer.parseInt() and use it!

{
    //  }
        if (args.length == 1)
            sender.sendMessage(NOT_ENOUGH_ARGUMENTS);
        else if ( !args[1].matches("-?\\d+"))
            // ** To not allow negative integers, remove '-?' **
            sender.sendMessage(NOT_INTEGER);
        else {
            int amount = Integer.parseInt(args[1]);
            // The rest is your job to finish...
        }
    }
    return false;
}

了解更多信息

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