如何获得从JSON解析return语句的结果？ [英] How to get the result for return statement from JSON parsing?
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问题描述
我已经按照code从这里 使用JSON解析的价值，但我得到的问题在我的return语句。我想提出的解析结果到我return语句。怎么做？
这里是我的code：
公共字符串目录注入（用户字符串，字符串密码）
{
SoapObject要求=新SoapObject（WSDL_TARGET_NAMESPACE，OPERATION_NAME）; PI的PropertyInfo =新的PropertyInfo（）;
pi.setName（ccduser）;
pi.setValue（用户）;
pi.setType（为String.class）;
request.addProperty（PI）; PI2的PropertyInfo =新的PropertyInfo（）;
pi2.setName（密码）;
pi2.setValue（密码）;
pi2.setType（为String.class）;
request.addProperty（PI2）;
SoapSerializationEnvelope信封=新SoapSerializationEnvelope（SoapEnvelope.VER11）;
envelope.dotNet = TRUE; envelope.setOutputSoapObject（请求）; HttpTransportSE httpTransport =新HttpTransportSE（SOAP_ADDRESS）;
尝试
{
httpTransport.call（SOAP_ACTION，信封）;
SoapObject resultSOAP =（SoapObject）envelope.bodyIn; / *得到我们的结果JSON字符串* /
串ResultObject = resultSOAP.getProperty（0）的ToString（）; resultSOAP =（SoapObject）envelope.bodyIn;
ResultObject = resultSOAP.getProperty（0）的ToString（）; 如果（ResultObject.startsWith（{））{//如果JSON字符串是一个对象
JSONObj =新的JSONObject（ResultObject）;
迭代器＆LT;串GT; ITR = JSONObj.keys（）;
而（itr.hasNext（））{
字符串键=（字符串）itr.next（）;
字符串值= JSONObj.getString（关键）;
BundleResult.putString（键，值）;
//的System.out.println（bundleResult.getString（关键））;
}
} 否则，如果（ResultObject.startsWith（[））{//如果JSON字符串数组
JSONArr =新JSONArray（ResultObject）;
的System.out.println（长度+ JSONArr.length（））;
的for（int i = 0; I＆LT; JSONArr.length（）;我++）{
JSONObj =（JSONObject的）JSONArr.get（I）
BundleResult.putString（将String.valueOf（ⅰ），JSONObj.toString（））;
//的System.out.println（bundleResult.getString（I））;
}
}
}
赶上（例外的例外）
{ } 返回null; }
解决方案
如果您有JSON数组对象：
的JSONObject jObject =新的JSONObject（*** JSON字符串你有***）;
JSONArray contestantObjects = jObject.getJSONArray（***阵列名称***）;
的for（int i = 0; I＆LT; contestantObjects.length（）;我++）{
mChannels.setId（contestantObjects.getJSONObject㈠.getString（ID）的toString（））;
mChannels.setName（contestantObjects.getJSONObject㈠.getString（名称）的toString（））;
}
如果你只有一个项目：
的JSONObject jObject =新的JSONObject（*** JSON字符串你有***）;
米preview.setBody（jObject.getString（***项目名称***）的toString（））;
米preview.setPublishedDate（jObject.getString（publishedDate）的toString（））;
米preview.setRefKey（jObject.getString（refKey）的toString（））;
米preview.setTitle（jObject.getString（题）的toString（））;
http://jsonviewer.stack.hu/ 是解析JSON在线工具。它的真棒，你可以使用它。
I've follow the code for parsing the value with JSON from here, but I get the problem in my return statement. I want to put the parsing result into my return statement. How to do that?
Here is my code:
public String MASUK(String user, String password)
{
SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME);
PropertyInfo pi = new PropertyInfo();
pi.setName("ccduser");
pi.setValue(user);
pi.setType(String.class);
request.addProperty(pi);
PropertyInfo pi2 = new PropertyInfo();
pi2.setName("password");
pi2.setValue(password);
pi2.setType(String.class);
request.addProperty(pi2);
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet = true;
envelope.setOutputSoapObject(request);
HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS);
try
{
httpTransport.call(SOAP_ACTION, envelope);
SoapObject resultSOAP = (SoapObject) envelope.bodyIn;
/* gets our result in JSON String */
String ResultObject = resultSOAP.getProperty(0).toString();
resultSOAP = (SoapObject) envelope.bodyIn;
ResultObject = resultSOAP.getProperty(0).toString();
if (ResultObject.startsWith("{")) { // if JSON string is an object
JSONObj = new JSONObject(ResultObject);
Iterator<String> itr = JSONObj.keys();
while (itr.hasNext()) {
String Key = (String) itr.next();
String Value = JSONObj.getString(Key);
BundleResult.putString(Key, Value);
// System.out.println(bundleResult.getString(Key));
}
}
else if (ResultObject.startsWith("[")) { // if JSON string is an array
JSONArr = new JSONArray(ResultObject);
System.out.println("length" + JSONArr.length());
for (int i = 0; i < JSONArr.length(); i++) {
JSONObj = (JSONObject) JSONArr.get(i);
BundleResult.putString(String.valueOf(i), JSONObj.toString());
// System.out.println(bundleResult.getString(i));
}
}
}
catch (Exception exception)
{
}
return null;
}
解决方案
If you have JSON array object:
JSONObject jObject = new JSONObject(***JSON String you have ***);
JSONArray contestantObjects = jObject.getJSONArray("*** Array Name ***");
for(int i=0; i<contestantObjects.length(); i++) {
mChannels.setId(contestantObjects.getJSONObject(i).getString("id").toString());
mChannels.setName(contestantObjects.getJSONObject(i).getString("name").toString());
}
If you have just one item:
JSONObject jObject = new JSONObject(***JSON String you have ***);
mPreview.setBody(jObject.getString("*** Item Name ***").toString());
mPreview.setPublishedDate(jObject.getString("publishedDate").toString());
mPreview.setRefKey(jObject.getString("refKey").toString());
mPreview.setTitle(jObject.getString("title").toString());
http://jsonviewer.stack.hu/ is online tool for parsing JSON. its awesome you can use it.
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