无法在glsl中使用'％' [英] Unable to use '%' in glsl

问题描述

今天在编写着色器程序时，遇到一种情况，我必须使用%查找其余部分. GLSL给我一个错误，说它在当前版本中不可用.

While writing a shader program today, I encountered a situation where I have to use % to find the remainder. GLSL gave me an error saying that it is not available in the current version.

我尝试了几个问题. GLSL不支持递归函数和while循环，如果我想创建一个可以给我(a % b)结果的函数，则需要GLSL.

I've tried several problems. GLSL doesn't support recursive function and while loops, which is needed if I want to create a function that can give me the result of (a % b).

所以，我目前陷入困境.有人可以帮我吗?

So, I'm currently stuck. Can someone help me with this?

修改.我试图使用此网站作为参考代码.我想修改某些行和列上像素的颜色，所以我需要使用模运算符.

Edit. I was trying to emulate a CRT screen using some shader code from this website as reference code. I wanted to modify the color of the pixels at certain row and columns, so I needed to make use of the modulo operator.

起初，我认为模量函数是使用%运算符完成的.它没有用，所以我尝试使用递归函数/while循环作为解决方法 用于模数函数，该函数也不起作用.

At first, I thought that the modulus function was done using the % operator. It didn't work, so I tried using recursive function/while loop as a workaround for modulus function, which didn't work either.

推荐答案

GLSL不支持递归函数和while循环，如果我想创建一个可以给我(a％b)结果的函数，则需要这.

GLSL doesn't support recursive function and while loops, which is needed if I want to create a function that can give me the result of (a % b).

首先，递归或循环对于计算a mod b都是不必要的. a - (b * floor(a/b))可以轻松做到这一点.

First, neither recursion nor looping is necessary to compute a mod b. That's easily done by a - (b * floor(a/b)).

这正是内置mod函数的功能.如果您的GLSL版本不支持%运算符，则您也可能无法获得实数.因此，只需在值上使用mod函数即可.

Which is exactly what the built-in mod function does. If your version of GLSL doesn't support the % operator, then you're probably not able to get real integers either. So just use the mod function on your values.

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