传入的参数必须是24个十六进制字符的字符串-我认为是 [英] Argument passed in must be a string of 24 hex characters - I think it is

问题描述

我有一种方法可以根据其ObjectID在数据库中查找文档:

I have a method to find a document in my database based on its ObjectID:

      console.log('id: ' + id + ' type: ' + typeof id);
      collection.findOne({'_id':new ObjectID(id)}, function(error,doc) {
        if (error) {
          callback(error);
        } else {
           callback(null, doc);
        }
      });

当我运行它时，出现以下错误:

When I run it I get the following error:

/myPath/node_modules/monk/node_modules/mongoskin/node_modules/mongodb/lib/mongodb/connection/base.js:245
    throw message;      
          ^
Error: Argument passed in must be a single String of 12 bytes or a string of 24 hex characters
at new ObjectID (/myPath/node_modules/mongodb/node_modules/bson/lib/bson/objectid.js:38:11)
at /myPath/collectionDriver.js:134:41

这是指上面的collection.findOne()行.

在该调用之前，我拥有的控制台日志将id输出为24个十六进制字符的字符串:

The console log I have before that call outputs the id as a string of 24 hex characters:

id: "55153a8014829a865bbf700d" type: string

在此之前，我使用JSON.stringify()将id从对象转换为字符串，但是它似乎可以正常运行，如console.log中所示.

Before this I convert the id from an object to a string using JSON.stringify() but it appears to work successfully as shown in my console.log.

在Robomongo中运行db.myCollection.findOne({_id : ObjectId("55153a8014829a865bbf700d")})会带来预期的结果.

Running db.myCollection.findOne({_id : ObjectId("55153a8014829a865bbf700d")}) in Robomongo brings back the expected result.

推荐答案

在这种情况下，传递给我的函数的ID已经是一个对象ID，因此不需要从中创建新的ObjectID.

The id that was passed in to my function was already an object ID in this case, so did not need a new ObjectID to be created from it.

当ObjectID登录到控制台时，它们显示为十六进制字符串，而不是ObjectID("hexString")，因此我认为我需要将其转换以进行查找，但是它已经是我需要的格式.

When ObjectIDs are logged out to the console they appear as hex strings, rather than ObjectID("hexString"), so I thought I needed to convert it to do the find, but it was already in the format that I needed.

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