nodejs表达响应追加到列表中 [英] nodejs express response append into a list

问题描述

我在一条路由中有多个res.send，如何将它们全部附加到一个中并在末尾发送累积的列表? 我更喜欢以以下形式进行操作:

I have multiple res.send in one route, how can I append them all into one and send the accumulated list at the end? I prefer to do it in the following form:

{
"writer": {success message},
"archive": {success message},
 ...
}

和上面类似的另一个错误，用于列表错误. 这是代码:

and another one like above for the list errors. here is the code:

router.post('/some/route', function (req, res) {
    if (req.isLoggedIn()) {
        return res.status(403).json({});
    }
    MyModel.findById(req.user._id,function (err, data) {
        if(err || data.rights !== 'super'){
            return res.status(403).json({});
        }
        if(req.body.writer){
            Books.update(
                { writer : req.body.id},
                { $set : { writer : req.body.writer} },
                function (err) {
                    if(err){
                        res.status(500).send(err);
                    }
                    else{
                        res.status(200).send('updated successfully.');
                    }
                }
            );
        }else{
            Books.remove({writer: req.body.id}, function(err){
                if (err){ return console.log(err)}
            });
        }

        MetaInfo.findOneAndRemove({_id: req.body.id}, function (err, data) {
            console.log(err);            
        });
        Archive.findOne({_id: req.body.id},function (err, data) {

            smtpTransporter.sendMail({...}, function (error, response) {
                if (error) {
                    console.log(error);
                } else {
                    console.log("Mail sent");
                }
                smtpTransporter.close();
            });

            data.remove();
            if (err) {
                console.log(err);
                return res.status(200).json({
                    success: false,
                    message: 'server error',
                    err: err
                });
            }
            res.status(200).json({
                success: true
            });
        })
    });
});

推荐答案

我假设您的问题是对数据库的异步调用.

I assume your problem are the asynchronous calls to the database.

因此最好选择一个您选择的库(例如 async )，然后执行异步过程，然后在回调中发送结果.

So best take a library of your choice (for example async) and do your async processes, in the callback then finally send your result.

您的结果可能如下所示:

async.parallel([
    function(callback) { ... },
    function(callback) { ... }
], function(err, results) {
    // send your result here
});

请注意，如果您使用的是.parallel，则在其中一个诺言失败的情况下，将立即调用最终回调.参见 docu

Note that if you are using .parallel the final callback will be immediatly called if one of the promises fails. see the docu

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