Mysql-我如何通过交替(1,2,3，1，2，3，1，2，3，)行来排序结果，有可能吗? [英] Mysql - How do I order results by alternating (1,2,3, 1, 2, 3, 1, 2, 3,) rows, is it possible?

问题描述

我想按客户端1、2、3，然后再按客户端1、2、3等对我的结果进行排序.

I want to order my results by client 1, 2, 3, then again client 1, 2, 3, and so on.

有没有一种方法，而无需使用for循环或进行三个单独的查询?不仅如此，而且我正在处理分页数据，因此它需要返回x结果，但是要始终如一.

Is there a way to do this without using a for loop or making three separate queries? Not only that, but I am working with paginated data so it needs to return x results, but consistently.

有什么想法吗?也许是GROUP BY?

Any ideas? GROUP BY maybe?

client_id  project_id  project_name  
---------- ----------  ------------
 1         42          project abc
 2         49          project xyz
 3         41          project 123
 1         22          project apple
 2         29          project orange
 3         21          project banana

推荐答案

使用:

SELECT x.client_id, 
       x.project_id,
       x.project_name
  FROM (SELECT t.client_id,
               t.project_id,
               t.project_name,
               CASE
                 WHEN @client_id != t.client_id THEN @rownum := 0
                 WHEN @client_id = t.client_id THEN @rownum := @rownum + 1
                 ELSE @rownum 
               END AS rank,
               @client_id := t.client_id
          FROM TABLE t,
               (SELECT @rownum := 0, @client_id
      ORDER BY t.client_id) r) x
ORDER BY x.rank, x.client_id

MySQL没有任何排名功能，但是幸运的是您可以使用变量.关键是在client_id与先前的client_id不匹配时重置@rownum值-子查询中的ORDER BY是为了确保客户端顺序正确.

MySQL doesn't have any ranking functionality, but luckily you can use variables. The key was resetting the @rownum value when the client_id doesn't match the previous client_id - the ORDER BY in the subquery is to ensure that clients are in order.

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