python中函数的均方根 [英] Root mean square of a function in python

问题描述

我想计算Python中函数的均方根.我的函数采用y = f(x)的简单形式. x和y是数组.

I want to calculate root mean square of a function in Python. My function is in a simple form like y = f(x). x and y are arrays.

我尝试了 Numpy和Scipy文档，但找不到任何东西.

I tried Numpy and Scipy Docs and couldn't find anything.

推荐答案

我将假定您要计算以下伪代码给出的表达式:

I'm going to assume that you want to compute the expression given by the following pseudocode:

ms = 0
for i = 1 ... N
    ms = ms + y[i]^2
ms = ms / N
rms = sqrt(ms)

即y元素的平方值的平均值的平方根.

i.e. the square root of the mean of the squared values of elements of y.

在numpy中，您可以简单地将y平方，取其均值，然后平方根如下:

In numpy, you can simply square y, take its mean and then its square root as follows:

rms = np.sqrt(np.mean(y**2))

例如，

>>> y = np.array([0, 0, 1, 1, 0, 1, 0, 1, 1, 1])  # Six 1's
>>> y.size
10
>>> np.mean(y**2)
0.59999999999999998
>>> np.sqrt(np.mean(y**2))
0.7745966692414834

如果您想问其他问题，请澄清您的问题.

Do clarify your question if you mean to ask something else.

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