Python Numpy-复数-是否有将极坐标转换为矩形的函数? [英] Python Numpy - Complex Numbers - Is there a function for Polar to Rectangular conversion?

问题描述

是否有内置的Numpy函数将极性形式的复数，大小和角度(度)转换为实部和虚部的一个?

Is there a built-in Numpy function to convert a complex number in polar form, a magnitude and an angle (degrees) to one in real and imaginary components?

很明显，我可以编写自己的代码，但是似乎某些类型的事物的某个模块中包含了优化的版本?

Clearly I could write my own but it seems like the type of thing for which there is an optimised version included in some module?

更具体地说，我有一个幅度数组和一个角度数组:

More specifically, I have an array of magnitudes and an array of angles:

>>> a
array([1, 1, 1, 1, 1])
>>> b
array([120, 121, 120, 120, 121])

我想要的是:

>>> c
[(-0.5+0.8660254038j),(-0.515038074+0.8571673007j),(-0.5+0.8660254038j),(-0.5+0.8660254038j),(-0.515038074+0.8571673007j)]

推荐答案

没有功能可以完全满足您的需求，但是有

There isn't a function to do exactly what you want, but there is angle, which does the hardest part. So, for example, one could define two functions:

def P2R(radii, angles):
    return radii * exp(1j*angles)

def R2P(x):
    return abs(x), angle(x)

这些函数将弧度用于输入和输出，对于度数，在两个函数中都需要将弧度转换为弧度.

These functions are using radians for input and output, and for degrees, one would need to do the conversion to radians in both functions.

在numpy中参考有一个关于处理复数的部分，这里列出了您要查找的函数(因此，因为它们不存在，所以我认为它们不存在于numpy中).

In the numpy reference there's a section on handling complex numbers, and this is where the function you're looking for would be listed (so since they're not there, I don't think they exist within numpy).

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