np.transpose不返回矩阵的转置 [英] np.transpose doesn't return transpose of matrix

问题描述

当我以以下方式编写代码时:

When I write my code in the following manner :

from numpy import *
H = array([1,1])
Ht = transpose(H)
Ht

我得到与H相同的矩阵，而不是H的转置.

I get the same matrix as H instead of the transpose of H.

但是当我以以下方式更改矩阵H时:

But when I change the matrix H in the following way :

from numpy import *
H = array(([1,1],[2,3]))
Ht = transpose(H)
Ht

我得到H的转置.

我不明白这里发生了什么.是使用转置函数的方式还是定义矩阵的方式?

I fail to understand what is happening here. Is it the way transpose function is used or is it the way a matrix is defined?

推荐答案

我认为这是您要寻找的行为:

I think this is the behavior you're looking for:

>>> H = np.array([[1,1]])
>>> H.T
array([[1],
       [1]])

等效地，您可以编写np.transpose(H).请注意，此数组的形状为(1,2)，因此具有两个维度.数组H = np.array([1,2])具有形状(2,).它只有一个维度.要交换尺寸(转置)，您至少需要两个.

Equivalently you can write np.transpose(H). Notice this array has shape (1,2), so it has two dimensions. The array H = np.array([1,2]) has shape (2,). It only has one dimension. To swap the dimensions (transpose), you need at least two of them.

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