将更接近的白色像素分组在一起，并在OpenCV中围绕它们绘制一个矩形 [英] Group closer white pixels together and draw a rectangle around them in OpenCV

问题描述

我想对这些彼此靠近的白色像素进行分组，并使用C ++在OpenCV中围绕它们绘制一个矩形.

I want to group these white pixels that are closer to each other and draw a rectangle around them in OpenCV using C++.

原始图片:

预期结果:

我是OpenCV的新手.任何帮助将不胜感激.

I am new to OpenCV. Any help would be deeply appreciated.

推荐答案

您可以使用

You can group white pixels according to a given predicate using partition. In this case, your predicate could be: group all white pixels that are within a given euclidean distance.

然后您可以为每个组计算边界框，保留最大的框(在下面的红色)，并最终将其放大(在下面的绿色):

You can then compute the bounding boxes for each group, keep the largest box (in RED below), and eventually enlarge it (in GREEN below):

代码:

#include <opencv2\opencv.hpp>
#include <vector>
#include <algorithm>

using namespace std;
using namespace cv;

int main()
{
    // Load the image 
    Mat3b img = imread("path_to_image", IMREAD_COLOR);

    // Convert to grayscale
    Mat1b gray;
    cvtColor(img, gray, COLOR_BGR2GRAY);

    // Get binary mask (remove jpeg artifacts)
    gray = gray > 200;

    // Get all non black points
    vector<Point> pts;
    findNonZero(gray, pts);

    // Define the radius tolerance
    int th_distance = 50; // radius tolerance

    // Apply partition 
    // All pixels within the radius tolerance distance will belong to the same class (same label)
    vector<int> labels;

    // With lambda function (require C++11)
    int th2 = th_distance * th_distance;
    int n_labels = partition(pts, labels, [th2](const Point& lhs, const Point& rhs) {
        return ((lhs.x - rhs.x)*(lhs.x - rhs.x) + (lhs.y - rhs.y)*(lhs.y - rhs.y)) < th2;
    });

    // You can save all points in the same class in a vector (one for each class), just like findContours
    vector<vector<Point>> contours(n_labels);
    for (int i = 0; i < pts.size(); ++i)
    {
        contours[labels[i]].push_back(pts[i]);
    }

    // Get bounding boxes
    vector<Rect> boxes;
    for (int i = 0; i < contours.size(); ++i)
    {
        Rect box = boundingRect(contours[i]);
        boxes.push_back(box);
    }

    // Get largest bounding box
    Rect largest_box = *max_element(boxes.begin(), boxes.end(), [](const Rect& lhs, const Rect& rhs) {
        return lhs.area() < rhs.area();
    });

    // Draw largest bounding box in RED
    Mat3b res = img.clone();
    rectangle(res, largest_box, Scalar(0, 0, 255));

    // Draw enlarged BOX in GREEN
    Rect enlarged_box = largest_box + Size(20,20);
    enlarged_box -= Point(10,10);

    rectangle(res, enlarged_box, Scalar(0, 255, 0));


    imshow("Result", res);
    waitKey();

    return 0;
}

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