GLSL片段着色器语法错误 [英] GLSL fragment shader syntax error

问题描述

以下简单的片段着色器代码失败，使我在日志中没有提供任何信息: ERROR: 0:1: 'gl_Color' : syntax error syntax error

the following simple fragment shader code fails, leaving me with an uninformative message in the log: ERROR: 0:1: 'gl_Color' : syntax error syntax error

void main()
{
  vec4 myOutputColor(gl_Color);
  gl_FragColor = myOutputColor;
}

以下一项有效:

void main()
{
  glFragColor = gl_Color;
}

这令人困惑，例如 Lighthouse3D的教程 gl_Color是据说是vec4.为什么不能将其分配给另一个vec4?

This boggles my mind, as in Lighthouse3D's tutorial gl_Color is said to be a vec4. Why can't I assign it to another vec4?

推荐答案

尝试正常分配.像这样:

Try normal assignment. Like this:

void main()
{
  vec4 myOutputColor = gl_Color;
  gl_FragColor = myOutputColor;
}

第二个答案确实一样正确，但是不需要使用vec4()构造函数，因为两者的类型相同.如果让我们说一个(r，g，b，w)元组，则可以编写:

The second answer is just as correct really, but there isn't any need to use the vec4() constructor, since both are of the same type. If you had lets say a (r,g,b,w) tuple you could write:

vec4 myOutputColor = vec4(r, g, b, w);

或

// assuming myRgbColor is a vec3
vec4 myOutputColor = vec4(myRgbColor, w);

等

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