多态性:“指向绑定函数的指针只能用于调用该函数". [英] Polymorphism: "A pointer to a bound function may only be used to call the function"

问题描述

我将代码分成多个文件，但这是我不明白的一件事.

I'm separating my code into multiple files, but this is one thing I don't get.

在graphics.h中:

In graphics.h:

...
class graphics {
public:
virtual void SizeMod(int w, int h);
...
}

在graphics.cpp中:

In graphics.cpp:

...
void SizeMod(int w, int h) {
    //Code here.
}
...

在main.cpp中:

In main.cpp:

...
graphics g;
...
int main (int argc, char **argv) {
    ...
    glutReshapeFunc(g.SizeMod);
    ...
}

错误:

error C3867: 'graphics::SizeMod': function call missing argument list; use &graphics::SizeMod to create a pointer to member

所以我做到了:

...
graphics g;
...
int main (int argc, char **argv) {
    ...
    glutReshapeFunc(&graphics::SizeMod);
    ...
}

它仍然给我一个错误(一个不同的错误). 有什么办法解决这个问题吗?

It still gives me an error (a different one). Anything to solve this problem?

推荐答案

它不会以这种方式工作，因为SizeMod是非静态的类成员方法，因此需要调用this.您必须将SizeMod设为静态.

it won't work this way because SizeMod is a non-static class member method, so it needs this to be called on. You have to make SizeMod static.

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