数的Swift算术和比较运算符重载列表? [英] list of Swift arithmetic and comparison operator overloads for numbers?
问题描述
文档中是否有地方或可以在Xcode 6中动态查找的内容,可以显示所有已定义的数字重载运算符,例如二进制算术运算符和比较运算符?
Is there a place in the documentation or something I can look up dynamically in Xcode 6 that shows all the defined operator overloads for numbers such as the binary arithmetic and comparison operators?
Swift支持所有数字类型的四个标准算术运算符:
加法(+)
减法(-)
乘法(*)
除法(/)
Swift supports the four standard arithmetic operators for all number types:
Addition (+)
Subtraction (-)
Multiplication (*)
Division (/)
Swift支持所有标准C比较运算符:
等于(a == b)
不等于(a!= b)
大于(a> b)
小于(a< b)
大于或等于(a> = b)
小于或等于(a< = b)
Swift supports all standard C comparison operators:
Equal to (a == b)
Not equal to (a != b)
Greater than (a > b)
Less than (a < b)
Greater than or equal to (a >= b)
Less than or equal to (a <= b)
我想知道的原因是,我可以看到何时必须使用类型转换,何时不使用,因为两种兼容类型都有内置的运算符重载.
The reason I would like to know is so that I can see when I'll have to use type casting and when I won't because there is a built-in operator overload for two compatible types.
我对类型转换和自动升序有一个相关的问题,但是在发布之前,我想确保我了解Swift默认定义的规则.
I have a related question on type casting and automatic upscaling, but before I posted it I wanted to make sure I understand the rules Swift defines by default.
推荐答案
正如Martin所说,您可以看到一种头文件,该文件通过命令单击Int或其他某些Swift类型来声明这些功能.例如,乘法函数如下所示:
As Martin said, you can see a sort of header file that declares these functions by command-clicking Int or some other Swift type. For example the multiplication functions look like this:
func *(lhs: UInt8, rhs: UInt8) -> UInt8
func *(lhs: Float, rhs: Float) -> Float
func *(lhs: Int, rhs: Int) -> Int
func *(lhs: UInt, rhs: UInt) -> UInt
func *(lhs: Int64, rhs: Int64) -> Int64
func *(lhs: Float80, rhs: Float80) -> Float80
func *(lhs: Double, rhs: Double) -> Double
func *(lhs: UInt64, rhs: UInt64) -> UInt64
func *(lhs: Int32, rhs: Int32) -> Int32
func *(lhs: UInt32, rhs: UInt32) -> UInt32
func *(lhs: Int16, rhs: Int16) -> Int16
func *(lhs: UInt16, rhs: UInt16) -> UInt16
func *(lhs: Int8, rhs: Int8) -> Int8
所有算术函数均采用两个相同类型的数字,并返回该类型的数字.这就是为什么您经常必须在算术运算之前进行转换.
All of the arithmetic functions take two numbers of the same type and return a number of that type. That's why you often have to do conversions before arithmetic operations.
您只需要强制转换已经具有类型的变量或常量.您可以对原始数字文字进行任何算术运算.
You only have to cast variables or constants that already have a type. You can do any arithmetic operation on raw numeric literals.
在这种情况下,两个操作数都是常量,在定义它们时,swift隐式地为其赋予了类型:
In this situation both operands are constants and swift gave them a type implicitly when they were defined:
let a = 42 //compiler assumes Int
let b = 3.14 //compiler assumes Float
a + Int(b) //returns Int (45)
但这并不意味着将小数点后的值强制将文字分配给Float变量.您可以显式强制输入类型:
but that doesn't mean having a decimal point will force the literal to be assigned to a Float variable. You can explicitly force the type:
var x: Int = 1.1 //shows 1
var y: Float = 1 //shows 1.0
这就是为什么您可以做这样的事情:
That's why you can do stuff like this:
var foo = 10
foo + 10.4
即使10.4是浮点文字,因为Swift已经隐式地将foo键入为Integer,因此它也将10.4文字也视为Integer并愉快地将它们加在一起.
even though 10.4 is a floating-point literal, because Swift already implicitly typed foo as an Integer it treats the 10.4 literal as an Integer as well and happily adds them together.
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